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AveGali [126]
3 years ago
12

Why did you wrap test tube 2 and 5 in aluminium foil and not test tube 1 and 6?

Chemistry
1 answer:
Andrew [12]3 years ago
5 0
In the dark test tube carbon dioxide will be created, and will bring about the corrosiveness level in the water increment. In the light test tube carbon dioxide will be devoured, making the oxygen level ascent and make the corrosiveness level lessening.
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Sulfuric acid (h2so4) is spilled on a laboratory bench. which chemical would be useful for neutralizing the acid
marysya [2.9K]
Sulphuric acid (H2SO2) is a dibasic acid. It generated H+ ions when dissolved in water. In order to neutralize an acid, a base containing hydroxy ion (OH-) will be required. 

NaOH, Ca(OH)2, KOH, etc. can be used to neutralize H2SO4.

If NaOH is used as a base, following reaction is initiated.

2NaOH     +      H2SO4      →     Na2SO4     +     H2O     
 (base)                (acid)                  (salt)
8 0
3 years ago
Draw a Lewis Dot Structure for the following element P
Mkey [24]
Lewis dot structure for phosphorus

6 0
3 years ago
Which of the following is the largest volume?
Ede4ka [16]
The answer to the question is B.
3 0
3 years ago
RIGHT ANWSER WILL BE MARKED BRAINLIEST
dybincka [34]

Answer:

11460

Explanation:

4 0
3 years ago
Can you please help me and can you show your work please
natali 33 [55]

Answer:

1. 25 moles water.

2. 41.2 grams of sodium hydroxide.

3. 0.25 grams of sugar.

4. 340.6 grams of ammonia.

5. 4.5x10²³ molecules of sulfur dioxide.

Explanation:

Hello!

In this case, since the mole-mass-particles relationships are studied by considering the Avogadro's number for the formula units and the molar mass for the mass of one mole of substance, we proceed as shown below:

1. Here, we use the Avogadro's number to obtain the moles in the given molecules of water:

1.5x10^{25}molecules*\frac{1mol}{6.022x10^{23}molecules} =25 molH_2O

2. Here, since the molar mass of NaOH is 40.00 g/mol, we obtain:

1.2mol*\frac{40.00g}{1mol} =41.2g

3. Here, since the molar mass of C6H12O6 is 180.15 g/mol:

45g*\frac{1mol}{180.15g}=0.25g

4. Here, since the molar mass of ammonia is 17.03 g/mol:

20mol*\frac{17.03g}{1mol}=340.6g

5. Here, since the molar mass of SO2 is 64.06 g/mol:

48g*\frac{1mol}{64.06g} *\frac{6.022x10^{23}molecules}{1mol} =4.5x10^{23}molecules

Best regards!

5 0
3 years ago
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