The molality is calculated using the following rule:
molality = number of moles of solute / kg of solvent
From the periodic table:
molar mass of lithium = 6.941 gm
molar mass of chlorine = 35.453 gm
molar mass of LiCl = 6.941 + 35.453 = 42.394 gm
number of moles found in 42 gm = mass / molar mass = 42 / 42.394 = 0.99
molality = 0.99 / 3.6 = 0.275 m
The chemical element of atomic number 86, a rare radioactive gas belonging to the noble gas series.
The reason iodine, I2, exists as a solid at room temperature, while bromine, Br2, exists as a liquid at the same temperature, is because: <span>Iodine molecules create stronger London dispersion forces than do bromine molecules.</span>
Reaction 1 : yes
Reaction 2 : no
<h3>Further explanation</h3>
The metal activity series is expressed in voltaic series
Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au
The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent
The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent
So that the metal located on the left can push the metal on the right in the redox reaction
From activity series of Halogen :
F₂>Cl₂>Br₂>I₂
F₂ is the strongest oxidizing agent
1. Reaction
Cl₂ + 2Rbl - 2RbCI+ I₂
Cl₂>I₂⇒reaction can occur⇒yes, reactions will take place.
2. Reaction
I₂ + NiBr₂ - NI₂ + Br₂
Br₂>I₂⇒Reaction can't occur⇒no, reaction will not take place
The given question is incomplete. The complete question is:
Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis. Determine the mass of glucose (C6H1206) produced
Answer: 60.0 g of glucose
Explanation:
To calculate the moles, we use the equation:
a) moles of 
b) moles of 
According to stoichiometry :
6 moles of require = 6 moles of
Thus 2.0 moles of require=
of
Thus is the limiting reagent as it limits the formation of product.
As 6 moles of give = 1 moles of glucose
Thus 2.0 moles of give =
of glucose
Mass of glucose = 
Thus 60.0 g of glucose will be produced from 88.0 g of carbon dioxide and 64.0 g of water
