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3 years ago

Which direction does the sun to move across the sky

Chemistry

2 answers:

Ierofanga [76]3 years ago

6 0

Answer:

EAST is the answer

Explanation:

For the moment, let us just think about one motion - - Earth's spin (or rotation) on its axis. Earth rotates or spins toward the east, and that's why the Sun, Moon, planets, and stars all rise in the east and make their way westward across the sky.

sineoko [7]3 years ago

6 0

Answer:

The Sun, although it appears so, does not actually move across the sky.

However, it appears to go west

I hope this helps

Explanation:

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The fermentation of C6H12O6 will produce carbon dioxide and

Leokris [45]

Answer:

ethanol

Explanation:

CO2 is carbon dioxide

C2H5OH is ethanol and we know that because that is what is left after taking out the CO2

5 0

2 years ago

How many gallons of gasoline that is 5% ethanol must be added to 2,000 gallons of gasoline with no ethanol to get a mixture that

Amanda [17]

Answer:

$V_1= 3000 gal$

Explanation:

We have 3 solutions:

Solution 1 (with ethanol)
Solution 2 (no ethanol)
Final solution

$V_f=V_1 + V_2$

and for the ethanol:

$V_f*0.03=V_1*0.05 + V_2*0$

$V_f=V_1 \frac{5}{3}$

Combining:

$V_1 \frac{5}{3}=V_1 + V_2$

$V_1 \frac{2}{3}= V_2$

$V_1= \frac{3}{2} V_2$

If V2=2000 gal:

$V_1= \frac{3}{2} 2000 gal$

$V_1= 3000 gal$

8 0

3 years ago

Why would satellite imagery be more useful than a map in some instances? provides landmarks, such as buildings can be used when

miss Akunina [59]

Answer:c

Explanation:

7 0

3 years ago

Mass, size, and color are examples of what?

Igoryamba

Physical properties of matter

3 0

3 years ago

Calculate the molar solubility of CaF2 at 25°C in a solution that is 0.010 M in Ca(NO3)2. The Ksp for CaF2 is 3.9 x 10-11.

madreJ [45]

Answer:

$Molar \ solubility=3.12x10^{-5}M$

Explanation:

Hello,

In this case, for the dissociation of calcium fluoride:

$CaF_2(s)\rightleftharpoons Ca^{2+}+2F^-$

The equilibrium expression is:

$Ksp=[Ca^{2+}][F^-]^2$

In such a way, via the ICE procedure, including an initial concentration of calcium of 0.01 M (due to the calcium nitrate solution), the reaction extent $x$ is computed as follows:

$3.9x10^{-11}=(0.01+x)(2*x)^2\\\\x=0.0000312M$

Thus, the molar solubility equals the reaction extent $x$ , therefore:

$Molar \ solubility=3.12x10^{-5}M$

Regards.

4 0

3 years ago