Answer:
1,700feet
Explanation:
If an object in free fall travels a distance s that is directly proportional to the square of the time t, this can be represented mathematically as;
S = kt²where;
k is the proportionality constant
K = s/t²
s1/t1²= s2/t2²= Sn/tn²= k for values of the distance and time. Using the formula
s1/t1² = s2/t2² where;
s1 is the falling distance in time t1 s2 is the falling distance in time t2
Given s1 = 1088feet, t1 = 8secs, s2 = ? t2 = 10secs
Substituting this value in the formula to get s2, we have;
1088/8²= s2/10²
64s2= 108800
s2 = 108800/64
s2 = 1,700feet
This means the object will fall a distance of 1,700feet in 10seconds
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hope it helps
The required work to hold the crate above the ground is 150 joule.
We need to know about the work done to solve this problem. The work done by an object depends on the force applied and the distance. The work is proportional to force and displacement. It can be written as
W = F . s
where W is work done, F is the force and s is displacement
From the question above, the given parameters are
F = 100 N
s = 1.5
Thus, the required work to hold the crate above the ground can be calculated
W = F . s
W = 100 . 1.5
W = 150 joule
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Answer:
So an MA of 1 then 2 newtons would be required to lift 20 KG
F = Mass Acceleration = 20 x 10 = 200 Newtons so to lift the same mass with 50 newtons then the mechanical advantage hast to be 200 divided by 50 = 4
