An example of a balanced force would be a book sitting on a shelf untouched.
Isaac Newton’s First Law of Motion states that an object at motion stays in motion, and an object at rest stays at rest until acted on by an unbalanced force. A book sitting still is an example of a balanced force because nothing is acting on it; its potential energy is stored while it’s at rest. For this book to become an unbalanced force, an outside force would have to occur (i.e pushing the book or dropping it) that causes it to not be in a state of stillness.
Answer:
Explanation:
As B has a y component of -5, A must have a y component of 5 to have the result lie on the x axis.
As B has an x component of 3 and the result has an x component of -4, A must have an x component of -7
A = (-7, 5)
magnitude A = √(7² + 5²) = √74 ≈ 8.60
θ = arctan(y/x) = arctan(5/-7) ≈ 144.46° CCW from the positive x axis
The motion of the ball is a composition of two motions:
- on the x (horizontal) axis, it is a uniform motion with initial velocity

- on the y (vertical) axis, it is a uniformly accelerated motion with acceleration
(a) to solve this part, we just analyze the motion on the vertical axis. The law of motion here is

By requiring y(t)=0, we find the time t at which the ball reaches the floor:


(b) for this part, we can analyze only the motion on the horizontal axis. To find how far the ball will land, we must calculate the distance covered on the x-axis, x(t), when the ball reaches the ground (so, after a time t=0.64 s):
Answer:
The weight of the wheelbarrow and the road is 784 N and the force required to lift the wheelbarrow is 784 N.
Explanation:
Given that,
The total mass of the wheelbarrow and the road is 80 kg.
The weight of an object is given by :
W = mg
where
g is acceleration due to gravity
So,
W = 80 × 9.8
= 784 N
So, the force required to lift the wheelbarrow is equal to its weight i.e. 784 N.
F = ma so u can plug in the given numbers and solve:
F = (2)(3)