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kaheart [24]
3 years ago
8

Find the mass. 10 points. Will give brainliest.

Physics
2 answers:
TiliK225 [7]3 years ago
7 0

Answer:

<h2>3.94 kg</h2>

Explanation:

Given,

Force ( f ) = 30 N

Acceleration(a) = 7.6 m/s

Now, Let's find the mass of the ball

Using the Newton's second law of motion:

We get:

force \:  = mass \:  \times acceleration

plug the value

30 \:  = m \:  \times 7.6

Use the commutative property to reorder the terms

30 = 7.6 \: m

Swap the sides of the equation

7.6m = 30

Divide both sides of the equation by 7.6

\frac{7.6 \: m}{7.6}  =  \frac{30}{7.6}

Calculate

m = 3.94 \: kg

Hope this helps..

Best regards!!

FinnZ [79.3K]3 years ago
4 0

Answer:

\displaystyle \boxed{\mathrm{3.95 \: kg }}

Explanation:

\mathrm{force \: (N) = mass \: (kg) \times acceleration \: (m/s^2)}

\mathrm{force = 30N}

\mathrm{acceleration = 7.6 \: m/s^2 }

\mathrm{Find \: the \: mass.}

\mathrm{30 = m \times 7.6}

\displaystyle \mathrm{m =\frac{30}{7.6} }

\displaystyle \mathrm{m = 3.947... }

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A small block of mass 20.0 grams is moving to the right on a horizontal frictionless surface with a speed of 0.68 m/s. The block
Usimov [2.4K]

Answer:

a) v'=-0.227\ m.s^{-1}

b) v=1.36\ m.s^{-1}

Explanation:

Given:

mass of the lighter block, m'=0.02\kg

velocity of the lighter block, u'=0.68\ m.s^{-1}

mass of the heavier block, m=0.04\ kg

velocity of the heavier block, u=0\ m.s^{-1}

a)

Using conservation of linear momentum:

m'.u'+m.u=m'.v'+m.v

where:

v'= final velocity of the lighter block

v= final velocity of the heavier block

m'.u'=m'.v'+m.v

m'(u'-v')=m.v ........................(1)

Since kinetic energy is conserved in elastic collision:

\frac{1}{2}m'.u'^2=\frac{1}{2}m'.v'^2+\frac{1}{2}m.v^2

m'(u'^2-v'^2)=m.v^2

m'(u'-v')(u'+v')= m.v^2

divide the above equation by eq. (1)

v=u'+v' .............................(2)

now we substitute the value of v from eq. (2) in eq. (1)

m'(u'-v')=m(u'+v')

\frac{m'+m}{m'-m} =\frac{u'}{v'}

\frac{0.02+0.04}{0.02-0.04} =\frac{0.68}{v'}

v'=-0.227\ m.s^{-1} (negative sign denotes that the direction is towards left)

b)

now we substitute the value of v' from eq. (2) in eq. (1)

m'(u'-v+u')=m.v

2m'.u'=(m-m')v

2\times 0.02\times 0.68=(0.04-0.02)\times v

v=1.36\ m.s^{-1}

6 0
3 years ago
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