If the framed picture is shaped like a square and has a 12 square foot surface area, then the answer is yes, it will fit flush against the edge of the crate.
Given Part A:
the volume of the cube = 64 cubic feet
therefore, ∛64 = 4 feet
hence one edge measures 4 feet.
Now for Part B:
the area of the square is 12 square feet.
hence, √12 = 3.36 feet.
we can observe that 3.46<4
which indicates that the area covered by the painting is less than that of the one side of the crate, which makes it easy for the painting to fit in the crate.
Hence the painting will fit a side of crate.
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While packing for their cross-country move, the Chen family uses a that has the shape of a cube. PART A PART B If the crate has the volume V = 64 cubic feet, The Chens want to pack a large, framed painting. If an area of 12 square feet , will the painting fit flat what is the length of one edge? the framed painting has the shape of a square with against a side of the crate? Explain.
First we will do -3 times everything in the parenthesis.
-3 times -4n = 12n
-3 times 30 = -90
SO,
12n - 90 = -30
+90 +90
12n = 60
divide 12 on both sides;
n = 5
This is your answer,
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Answer:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
(
0
, 1
)
Equation Form:
x
=
0
, y
=
1
Step-by-step explanation:
Graph.
y
=
−
5/
2
x
−
1
y
=
3
x
−
1
y
=
2/
5
x
+
1
y
=
5/
3
x
+
1
Answer:
radius = 7 units
Step-by-step explanation:
Given:
Radius = 7 units
Find area of 4 circles:
1 circle = π (7)² = 49π units²
4 circles = 49π x 4 = 196π units²
Find radius of sphere:
4πr² = 196π
r² = 49
r = 7
