1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mestny [16]
3 years ago
6

Help now im not trying to fail

Chemistry
2 answers:
Alekssandra [29.7K]3 years ago
5 0

Answer:

i cant see the whats in the picture

KIM [24]3 years ago
5 0
The answer is B, Geosphere.

Hope this helps! :)
You might be interested in
Which bent shape has more repulsion and a smaller bond angle?<br> bent 6A<br> bent 5A
Step2247 [10]
Bent 6A is the answer
8 0
3 years ago
Which family in the periodic table has elements that are silvery and lustrous?
IrinaVladis [17]
The correct answer is A. Alkali metals.
I hope this helped
6 0
3 years ago
Read 2 more answers
A baseball that is moving through the air has ____________ energy. <br> A. potential <br> B. kinetic
Lunna [17]

Answer:

kinetic

Explanation:

3 0
3 years ago
The reaction C4H8(g)⟶2C2H4(g) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ/mol.262 kJ/mol. At 600.0 K,600.0 K, the rate c
crimeas [40]

Answer : The rate constant at 785.0 K is, 1.45\times 10^{-2}s^{-1}

Explanation :

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at 600.0K = 6.1\times 10^{-8}s^{-1}

K_2 = rate constant at 785.0K = ?

Ea = activation energy for the reaction = 262 kJ/mole = 262000 J/mole

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 600.0K

T_2 = final temperature = 785.0K

Now put all the given values in this formula, we get:

\log (\frac{K_2}{6.1\times 10^{-8}s^{-1}})=\frac{262000J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{600.0K}-\frac{1}{785.0K}]

K_2=1.45\times 10^{-2}s^{-1}

Therefore, the rate constant at 785.0 K is, 1.45\times 10^{-2}s^{-1}

7 0
3 years ago
Draw the structure of the neutral product formed in the reaction of dimethyl malonate and methyl vinyl ketone.
Dmitriy789 [7]

Answer:

Explanation:

The reaction between dimethyl malonate which is an active methylene group with an (∝, β-unsaturated carbonyl compound) i.e methyl vinyl ketone is known as a Micheal Addition reaction. The reaction mechanism starts with the base attack on the β-carbon to remove the acidic ∝-hydrogens and form a carbanion. The carbanion formed(enolate ion) attacks the methyl vinyl ketone(i.e. a nucleophilic attack at the β-carbon) to give a Micheal addition product, this is followed by the protonation to give the neutral product.

3 0
3 years ago
Other questions:
  • In an acid/base lab, a student used blue litmus paper and placed it in the sample. It stayed blue. Then the student used red lit
    13·1 answer
  • What mass of nitrogen gas is required to react completely with 2.79 g of hydrogen gas to produce ammonia?
    15·1 answer
  • (tco 2) an atom has 6 protons, 8 neutrons, and 6 electrons. its atomic mass is
    11·1 answer
  • Which is the correct order of material in terms of reflectivity from least to greatest
    10·1 answer
  • Density is given in ____. a. Pa/cm3 c. g/s2 b. N/m2 d. g/cm3 Please select the best answer from the choices provided A B C D
    11·2 answers
  • Ammonium hydrogen sulfide NH4HS(s) decomposes on heating according to the reaction NH4HS(s) ↔ NH3(g) + H2S(g) At 25 °C the equil
    9·2 answers
  • 7. What is the total pressure of the following mixture of gases in a 20.0 L container at 298 K: 12.0 g He,
    5·1 answer
  • As liquid water boils and changes into water vapor (steam), what happens
    15·2 answers
  • A single gold atom has a mass of 197.0 amu. How many gold atoms are in a cube of gold that is 10.0 mm on each side (about the si
    10·1 answer
  • A kid walking around with a balloon on a summer day when the temperature outside is 300 k contains the volume of 4 l goes into a
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!