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3 years ago

What 2 factors impact gravitational pull?

Physics

1 answer:

HACTEHA [7]3 years ago

7 0

Answer:

When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them

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Wat is matter made of?

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Matter is made of the particles are called atoms!

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3 years ago

What is the second step in the scientific method

beks73 [17]

The steps of the scientific method are to: Ask a Question. Do Background Research. Construct a Hypothesis. Test Your Hypothesis by Doing an Experiment. Analyze Your Data and Draw a Conclusion.

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4 years ago

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How is energy involved in physical changes and in chemical changes?

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3 years ago

What is the difference between mutual flux, leakage flux and magnetizing flux

Lemur [1.5K]

In simple words, flux can be stated as the rate of flow of a fluid, radiant energy, or particles across a given area.

Explanation:

Mutual Flux:

The magnetic lines present in among two magnets or solenoid is mutual flux.
These are the lines in which the attraction and repulsion happens.
The SI unit of mutual flux is the Henry

Leakage Flux:

In simple words, it can be stated as the magnetic flux which does not follow the specially designed way in a magnetic circuit.
Leakage flux in the induction motor takes spot due to current runs through the essence of the induction motor.
The SI unit of Leakage flux is the Weber

Magnetizing flux

Magnetic flux is an analysis of the entire magnetic field which moves in a given field
In simple words can be defined as the Magnetic flux is what generates the field around a magnetic material.

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3 years ago

A stone is dropped into a river from a bridge at a height h above the water. Another stone is thrown vertically down at a time t

Mumz [18]

Answer:

$v_{y_0} = \frac{\frac{g}{2}t(t - 2\sqrt{\frac{2h}{g}})}{\sqrt{\frac{2h}{g}} - t}$

Explanation:

We will apply the equations of kinematics to both stones separately.

First stone:

Let us denote the time spent after the second stone is thrown as 'T'.

$y - y_0 = v_{y_0}(t+T) + \frac{1}{2}a(t+T)^2\\0 - h = 0 + \frac{1}{2}(-g)(t+T)^2\\(t+T)^2 = \frac{2h}{g}\\T = \sqrt{\frac{2h}{g}}-t$

Second stone:

$y - y_0 = v_{y_0}T + \frac{1}{2}aT^2\\0 - h = v_{y_0}T -\frac{1}{2}gT^2\\-h = v_{y_0}(\sqrt{\frac{2h}{g}} - t) - \frac{g}{2}(\sqrt{\frac{2h}{g}} - t)^2\\-h = v_{y_0}(\sqrt{\frac{2h}{g}} - t) - \frac{g}{2}(\frac{2h}{g} + t^2 - 2t\sqrt{\frac{2h}{g}})\\-h = v_{y_0}\sqrt{\frac{2h}{g}} - v_{y_0}t - h -\frac{g}{2}t^2 + gt\sqrt{\frac{2h}{g}}\\v_{y_0}(\sqrt{\frac{2h}{g}} - t) = \frac{g}{2}t^2 - gt\sqrt{\frac{2h}{g}}\\v_{y_0} = \frac{\frac{g}{2}t(t - 2\sqrt{\frac{2h}{g}})}{\sqrt{\frac{2h}{g}} - t}$

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3 years ago

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