What 2 factors impact gravitational pull?
1 answer:
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Answer:
0.453 m/s
Explanation:
Assuming the handle has diameter of 0.4 m while inner part diameter is 0.1 m then the circumference of outer part is where d is diameter and subscript h denote handle. By substituting 0.4 for the handle's diameter then cirxumference of outer part is
The rate of rotation will then be 1.81/1.256=1.441 rev/s
Similarly, circumference of inner part will be where subscript i represent inner. Substituting 0.1 for inner diameter then
The rate of rotation found for outer handle applies for inner hence speed will be 0.3142*1.441=0.453 m/s
To find:
The equation to find the period of oscillation.
Explanation:
The period of oscillation of a pendulum is directly proportional to the square root of the length of the pendulum and inversely proportional to the square root of the acceleration due to gravity.
Thus the period of a pendulum is given by the equation,
Where L is the length of the pendulum and g is the acceleration due to gravity.
On substituting the values of the length of the pendulum and the acceleration due to gravity at the point where the period of the pendulum is being measured, the above equation yields the value of the period of the pendulum.
Final answer:
The period of oscillation of a pendulum can be calculated using the equation,