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3 years ago

Find the work w1 done on the block by the force of magnitude f1 = 95.0 n as the block moves from xi = -5.00 cm to xf = 4.00 cm .

Physics

1 answer:

Vlad [161]3 years ago

5 0

<h3><u>Answer;</u></h3>

= 8.55 Joules

<h3><u>Explanation;</u></h3>

Work done is the product of force and the distance moved by an object.

Work done = Force × distance

Force = 95 Newtons

Distance = X2 -X1

= 4 - (-5)

= 9 cm

Thus;

work done = 95 × 9/100

<u>= 8.55 Joules </u>

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4 years ago

Steel is very stiff, and the Young's modulus for steel is unusually large, 2.0×1011 N/m2. A cube of steel 25 cm on a side suppor

TEA [102]

Answer:

Force (normal) = 833.85 N Compression = 1.67 x 10⁻⁸ m

Explanation:

Given data Young's Modulus (Y) = 2 x 10¹¹ N/m², Length of one side of cube = 25 cm = 0.25 m, mass of load = 85 kg

Normal force is the force exerted upon an object that is in contact with another stable object. This force would be applied by the surface onto the object in the same vector and is used to keep the object stable while it rests on a surface.

We know from Newton's Second Law that

F = ma where m is the mass and a is the acceleration (<em>in this case due to gravity</em>) hence, the normal opposing force to the load applied by the surface would be equal to the force applied on the surface by the weight of the load on the surface, So

F (normal) = M (load) x a = 85 x 9.81 = 833.85 N

Compression is the change in length of an object by the exertion of force upon it. Using the Young's Modulus formula we can find this change in the cube of steel. The Young's Modulus is given by

Y = (F/A)/(ΔL/L), where Y is the Young's Modulus, F is the Force being applied on the object, A is the cross sectional area on which the said force is applied, ΔL is the change in length due to said force being applied and L is the original Length of the side of the cross sectional area.

Solving this for ΔL, we can re- arrange the equation

ΔL = (F x L)/(Y x A) since area of square is L x L we can simplify the equation to get

ΔL = (F)/(Y x L), substitute the values

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4 years ago

A vector A⃗ has a length of 8.6 m and points in the negative x direction. Find the x component of the vector −3.7A⃗ .

77julia77 [94]

Answer:

31.8 m in the positive x-direction

Explanation:

Here we have an example of multiplication of a vector by a scalar.

In order to perform this operation, we have to:

- multiply the magnitude of the vector by the scalar

- reverse the direction of the vector if the scalar is a negative number

In this problem, the original vector has a lenght of 8.6 m and it points in the negative x direction. Now we have to find the vector -3.7A, so we have:

- The magnitude is obtained by calculating the product

$(3.7)\cdot (8.6)=31.8 m$

- The direction is reversed, because the scalar is -3.7, so the new vector will point in the positive x-direction

So the final vector is 31.8 m in the positive x-direction, and therefore its x-component is also 31.8 m in the positive direction.

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