All categories

3 years ago

If an object moves in a straight line with position function s = f(t), then the average velocity between t = a and t = b is

Mathematics

1 answer:

Hunter-Best [27]3 years ago

3 0

Answer:

75 km/hr

Step-by-step explanation:

So, if a car travels 150 km in 2hours.

Then;

f(t=0) = 0

f(t = 2 hours) = 150 km

Therefore;

f'(c) (speedometer reading) = f(t=2)-f(t=0)/(2-0)

f'(c) (speedometer reading) = 150/2 km/hr

f'(c) (speedometer reading) = 75 km/hr

You might be interested in

In 4 hours you hike 10 miles which unit rate describes your speed on the hike 5 miles per hour 2.5 miles per hr 4/10 miles per h

Vikentia [17]

2.5 miles per hour because you have to divide to know per hour.
10/4=2.5
Done :)

4 0

3 years ago

Joley is opening her first checking account as a teenager. She doesn’t have a job, so most of the income will be presents from b

Stella [2.4K]

The answer is A. The reason for this is because 2% of $300 is $6. Since 6 is less than 8, the answer is A.

3 0

3 years ago

under a dilation, the point (2,6) is moved to (6,18) what is the scale factor of the dilation? enter your answer in the box

Anestetic [448]

Step-by-step explanation:

The equation of line passing through the two points is $\frac{y-y_{1} }{x-x_{1} }=\frac{y_{2} -y_{1}}{x_{2} -x_{1}}$

When substituted,the equation becomes $\frac{y-6}{x-2}=\frac{18-6}{6-2}$

which when simplified is $y=3\times x$

The line clearly passes through origin.

The distance between two points is $\sqrt{(y_{1}-y_{2} )^{2}+(x_{1}- x_{2} )^{2}}$

Distance between origin and $(2,6)$ is $\sqrt{40}$ .

Distance between origin and $(6,18)$ is $\sqrt{360}$

Scale factor is $\frac{distance\text{ }of\text{ }p_{2}\text{ from origin}}{distance \text{ } of \text{ } p_{1}\text{ from origin}}$

So,scale factor is $\frac{\sqrt{360} }{\sqrt{40} }$

which when simplified becomes 3.

6 0

3 years ago

Sam is filling up his pool. The water hose filled the 392 gallon pool in 49 minutes. At what rate did the hose fill the pool in

cestrela7 [59]

Your answer would be 8 Hammond per minute. Hope this helps!

3 0

3 years ago

Read 2 more answers

1. (a) Use the integral test to show that P[infinity] n=1 1/n4 converges. (b) Find the 10th partial sum, s10, of the series P[in

scZoUnD [109]

Answer:

Step-by-step explanation:

a) $\int\limits^{\infty} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}$

Substitute limits to get

= $\frac{1}{3}$

Thus converges.

b) 10th partial sum =

$\int\limits^{10} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}$

= $\frac{-1}{3} (0.001-1)\\= 0.333$

c) Z [infinity] n+1 1 /x ^4 dx ≤ s − sn ≤ Z [infinity] n 1 /x^ 4 dx, (1)

where s is the sum of P[infinity] n=1 1/n4 and sn is the nth partial sum of P[infinity] n=1 1/n4 .

(question is not clear)

3 0

3 years ago