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borishaifa [10]
2 years ago
7

Help with this please

Mathematics
2 answers:
Brut [27]2 years ago
8 0

Answer:

1. area = 16.492

2. area = 19.798

3. area = 15.874

4. area = 13.555

5. area = 12.349

6. area = 24.37

<em>good luck, i hope this helps :)</em>

Mariulka [41]2 years ago
8 0

Answer:

1) A=16.49    2)19.8     3)15.87    4)13.56      5)14.44    6)27.04

Step-by-step explanation:

for the first 4 you should use the pythagorean theorem a^2 + b^ = c^2 to find the missing side than you use (base*Leg)/2 to find the area

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Negative Exponents- All of the following expressions are equal except _____.
UNO [17]

7 is not equal to the others

using the laws of exponents

7^{2} / 7^{3} = 1 / 7^{3-2} = \frac{1}{7}

7^{-1} = \frac{1}{7}

Apart from 7 the other 3 all equal \frac{1}{7}





4 0
2 years ago
Find the product of (4x - 3 ()2x^2 - 7x + 1)
Paul [167]
Asked and answered at brainly.com/question/8532103
4 0
3 years ago
Find the highest common factor (HCF) of 72 and 98.​
Y_Kistochka [10]

<em>Answer:</em>

<em>2</em>

<em>Step-by-step explanation:</em>

<em>The factors of 72: 1, </em><em>2</em><em>, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72</em>

<em>The factors of 98: 1, </em><em>2</em><em>, 7, 14, 49, 98 </em>

<em>Your greatest common factor is 2.</em>

<em>Hope this helps. Have a nice day.</em>

3 0
3 years ago
18
Cloud [144]

Answer: 100

5

Step-by-step explanation:

a) The mean of a normal distribution is also the median. Half the population will have values above the mean. Half of 200 is 100, so ...

... 100 students will have grades above 70%.

b) 84% is 14% above the mean. Each 7% is 1 standard deviation, so 14% is 2 standard deviations above the mean. The empirical rule tells you 95% of the population is within 2 standard deviations of the mean, so about 5% of students (10 students) got grades higher than 84% or lower than 56%. The normal distribution is symmetrical, so we expect about 5 students in each range.

... about 5 students will have grades above 84%.

3 0
3 years ago
Parabolas y=−2x^2 and y=2x^2 +k intersect at points A and B that are in the third and the fourth quadrants respectively. Find k
OverLord2011 [107]

Answer:

-25  

Step-by-step explanation:

(1)   y = -2x²

(2) y =   2x² + k     Subtract (1) from (2)

    0 =  4x² + k      Subtract 4x² from each side

    k = -4x²

The parabolas are <em>symmetrical about the y-axis.</em>

Segment AB = 5, so x = +2.5 and x = +2.5.

k = -4(±2.5)² = -4 × 6.25 = -25

8 0
3 years ago
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