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Taya2010 [7]
2 years ago
15

An airplane flying horizontally at 130.0 m/s drops a crate of food from a height of 2750. m. How far in front of the target must

the bomb be released?
Physics
1 answer:
Airida [17]2 years ago
4 0

Answer:

<em>The crate should be released 3,080 m in front of the target</em>

Explanation:

<u>Horizontal Launch </u>

When an object is thrown horizontally with a speed v from a height of h, it describes a curved path ruled by gravity until it hits the ground.

The range or maximum horizontal distance traveled by the object can be calculated as follows:

\displaystyle d=v\cdot\sqrt{\frac  {2h}{g}}

The airplane drops a crate horizontally from a height of h= 2,750 m when flying at v=130 m/s. The range or maximum horizontal distance the crate reaches is:

\displaystyle d=130\cdot\sqrt{\frac  {2*2,750}{9.8}}

Operating:

\displaystyle d=130\cdot\sqrt{561.2245}

d = 3,080 m

The crate should be released 3,080 m in front of the target

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