What is the net force acting on this box?

In a football game a kicker attempts a field goal. The ball remains in contact with the kicker's foot for 0.0800 s, during which

Elena-2011 [213]

The initial velocity of the ball is 0. Applying:
v = u + at
v = 0 + 229 x 0.08
v = 18.3 m/s

a)
Vx = Vcos(∅)
Vx = 18.3cos(52.3)
Vx = 11.2 m/s

b)
Vy = Vsin(∅)
Vy = 18.3sin(52.3)
Vy = 14.5 m/s

5 0

3 years ago

A block is held at rest against a wall by a force of magnitude F exerted at an angle theta from the horizontal, as shown in the

wel

Answers:

B.) $F cos\theta=F_{n}$

C.) $F sin\theta=F_{g} \pm F_{f}$

Explanation:

The image attached shows the way the force $F$ is acting on the block. Now, if we draw a free body diagram of the situation and write the equations for the Net Force in X and Y, we will have the following:

Net Force in X:

$-F_{n}+F cos\theta=0$ (1)

Where:

$F_{n}$ is the Normal force

$F$ is the magnitude of the force exerted on the block

$\theta$ is the angle

Net Force in Y:

$F sin\theta \pm F_{f}-F_{g}=0$ (2)

Where:

$F_{f}$ is the Friction force (it is expresed with the $\pm$ sign because this force may be up or down, we cannot know because the block is at rest)

$F_{g}$ is the gravity force

Rewrittin (1):

$F cos\theta=F_{n}$ (3) This is according to option B

Rewritting (2):

$F sin\theta=F_{g}\pm F_{f}$ (3) This is according to option C

3 0

3 years ago

A neurogenic bladder is a urinary problem caused by interference with the normal __________ associated with urination.

Elena L [17]

Answer:

nerve pathways

Explanation:

It is called Neurogenic Bladder (VN) to any alteration of bladder behavior due to a pathology of the central and / or peripheral nervous system. It may consist of the loss of storage and / or urine disposal capabilities. Thus, a lesion in the upper centers causes variation in storage capacity, but if peripheral innervation is affected, loss of emptying capacity occurs. In the case of patients with spinal cord injury (ML) there are changes in both at the same time.

3 0

3 years ago

A 1700kg rhino charges at a speed of 50.0km/h. what average force is needed to bring the rhino to a stop in 0.50s?

uranmaximum [27]

From 50km/h to 0km/h in 0.5s we need next acceleration:
First we convert km/h in m/s:
50km/h = 50*1000/3600=13.8888 m/s
a = v/t = 13.88888/0.5 = 27.77777 m/s^2

Now we use Newton's law:

F=m*a

F=1700*27.7777 = 47222N

6 0

3 years ago

A negative slope on the velocity vs. time graph indicates that the object is not accelerating

liubo4ka [24]

AnswerNo

However, the acceleration is the opposite of the movement:

Explanation:

8 0

2 years ago