Acceleration........................................
<h2><u>FORMAT</u><u>ION</u></h2>
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Our solar system formed about 4.5 billion years ago from a dense cloud of interstellar gas and dust. The cloud collapsed, possibly due to the shockwave of a nearby exploding star, called a supernova. When this dust cloud collapsed, it formed a solar nebula—a spinning, swirling disk of material
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Hope It Helps!
Answer:

Explanation:
The planet can be thought as a solid sphere rotating around its axis. The moment of inertia of a solid sphere rotating arount the axis is

where
M is the mass
R is the radius
For the planet in the problem, we have


Solving the equation for R, we find the radius of the planet:

The maximum rate at which energy can be added to the circuit element mathematically given as

<h3>What is the maximum rate at which
energy can be added to the
circuit element?</h3>
Generally, the equation for P is mathematically given as

Therefore



Max temp Change


t=180s
In conclusion, Max Energy Rate


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Answer:
15.13 m/s
Explanation:
The wave speed of the stretched rope can be calculated using the following formula

where
is the tension on the rope and
is the density of the rope per unit length
