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Ivenika [448]
3 years ago
15

The compound magnesium phosphate has the chemical formula Mg3(PO4)2. In this compound, phosphorous and oxygen act together as on

e charged particle, which is connected to magnesium, the other charged particle.
What does the 2 mean in the formula 5Mg3(PO4)2?

There are two elements in magnesium phosphate.
There are two molecules of magnesium phosphate.
There are two magnesium ions in a molecule of magnesium phosphate.
There are two phosphate ions in a molecule of magnesium phosphate.
Physics
2 answers:
zepelin [54]3 years ago
8 0
The 2 means there are two phosphate ions in a molecule of magnesium phosphate.
-Dominant- [34]3 years ago
6 0

Answer:

There are two phosphate ions in a molecule of magnesium phosphate.

Explanation:

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How deep can an object with 6360N hitting on a sponge get ???
borishaifa [10]

Answer:

The sponge must go \dfrac{636}{m}\ \text{meter} deep

Explanation:

If F = 6360 N, then it is required to find how deep can an object with this force hitting on a sponge get.

We know that, F = mgh

m is mass

g is acceleration due to gravity

h=\dfrac{F}{mg}\\\\h=\dfrac{6360}{10m}\\\\h=\dfrac{636}{m}\ \text{meter}

So, the sponge must go \dfrac{636}{m}\ \text{meter} deep.

5 0
4 years ago
Thorium^+2
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Answer:

chemical symbol: Th

atomic number:90

protrons :90

neutrons:142

group#:4

period#: 9

Explanation:

you take the atomic weight (232.038)and subtract the atomic number to get (90) which is your neutrons

6 0
3 years ago
What is the momentum of an 18-kg object moving at 0.5 m/s?
Otrada [13]

sorry Idk the answer ..???

6 0
3 years ago
The graph in the accompanying figure (Figure 1) shows the magnitude of the force exerted by a given spring as a function of the
serious [3.7K]

The elastic potential energy stored in the stretched spring is 1 J.

<h3>What is Hooke's law?</h3>

Hooke's law states that; provided the elastic limit is not exceeded, the extension of the spring is directly proportional to the force on the spring.

Given that;

Force on the spring = 350 Newton

Distance stretched = 7 centimeters or 0.07 m

Hence;

F = ke

k = F/e = 350 Newton/0.07 m = 5000 N/m

Work done in stretching a spring = 1/2ke^2

= 0.5 × 5000 × (2 × 10^-2)^2 =1 J

Learn more about elastic potential energy: brainly.com/question/156316

4 0
2 years ago
The common version of Newton’s second law of motion, EF= ma, is actually a special case that is true only when an objects _____
vladimir2022 [97]

Answer:

A

Explanation:

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6 0
3 years ago
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