Answer:
im not confident bet i can try.
Answer:
Explanation:
We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.
MM: 102.89 159.81
2NaBr + F₂ ⟶ 2NaF + Br₂
m/g: 25.4
(a) Moles of Br₂
(b) Moles of NaBr
(c) Mass of NaBr
Answer:
958 g is the mass of LiOH that can react with all the CO₂
Explanation:
CO₂(g) + 2 LiOH(s) → Li₂CO₃(aq) + H₂O
We think in the reaction:
1 mol of carbon dioxide can react with 2 moles of lithium hydroxide.
First of all, we convert the mass of our reactant to mol:
880 g . 1mol /44g = 20 moles
As ratio is 1:2, 20 moles of CO₂ will react with 40 moles of LiOH.
Let's determine the mass:
40 mol . 23.95 g /1mol = 958 g
Answer:
It is (c) because acceleration is the of velocity with time
Answer:
10.9 * 10^-7 m
Explanation:
We know that the Rydberg constant (R) is – 13.6 eV = -2.18 * 10^-18 J
ΔE= -R(1/nf - 1/ni)
Where;
nf = final state
ni= initial state
ΔE= -2.18 * 10^-18(1/3 - 1/4)
ΔE= -2.18 * 10^-18(1/12)
ΔE= -1.81 * 10^-19 J
From;
ΔE=hc/λ
h = plank's constant = 6.6 * 10^-34 Js
c = 3 * 10^8 ms-1
λ = ?
λ = hc/ΔE
λ = 6.6 * 10^-34 * 3 * 10^8/ 1.81 * 10^-19
λ = 10.9 * 10^-7 m