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igomit [66]
3 years ago
9

Y=x2+8x+10. complete the square

Mathematics
2 answers:
Rasek [7]3 years ago
8 0
Y=10x+10
add the like terms together
goblinko [34]3 years ago
3 0
The answer is

y = (x+4)^2 -6
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Write an<br> equation in point slope form that passes through (25,32) with a slope of -4
Margaret [11]

Answer:

y-32=-4(x-25) point slope form

Step-by-step explanation:

y-y1=m(x-x1)

y-32=-4(x-25)

3 0
3 years ago
The rectangle below has an area of 8x^5+12x^3+20x^2.
Y_Kistochka [10]

Answer:

The width of the rectangle is 4x^24x

2

4, x, squared

The length of the rectangle is 2x^3+3x+52x

3

+3x+5

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
Rachna borrowed a certain sum at the rate of 15% per annum. if she paid at the end of the two years Rs.1290 as interest Compound
Natalija [7]

Given info:

Compound Interest = Rs.1290

Rate of Interest = 15% p.a

Time = 2 years

<h3>Formula we have to know:-</h3>

\dag{\underline{\boxed{\sf{C.I = P  \bigg(1  + \dfrac{R}{100} \bigg)^{n}  - 1}}}}

<u>Where</u>

C.I = Compound Interest

P = Principle

R = Rate of Interest

N = Time

\textsf{ \underline{Solution-}}\\

Here

C.I = Rs.1290

R = 15%

N = 2 years

Principle = ?

Now,Calculating the sum (Principle) borrowed by Rachna

\quad{: \implies{\sf{C.I =  \Bigg[P  \bigg(1  + \dfrac{R}{100} \bigg)^{n}  - 1 \Bigg]}}}

Substituting the given values

\quad{: \implies{\sf{1290 =  \Bigg[P  \bigg(1  + \dfrac{15}{100} \bigg)^{2}  - 1 \Bigg]}}}

\quad{: \implies{\sf{1290 =  \Bigg[P  \bigg(\dfrac{(1 \times 100) + 15}{100} \bigg)^{2}  - 1 \Bigg]}}}

\quad{: \implies{\sf{1290 =  \Bigg[P  \bigg(\dfrac{115}{100} \bigg)^{2}  - 1 \Bigg]}}}

\quad{: \implies{\sf{1290 =  \Bigg[P  \bigg(\dfrac{115}{100} \times \dfrac{115}{100}  \bigg)  - 1 \Bigg]}}}

\quad{: \implies{\sf{1290 =  \Bigg[P  \bigg(\dfrac{13225}{10000} \bigg) - 1 \Bigg]}}}

\quad{: \implies{\sf{1290 =  \Bigg[P  \bigg( \cancel{\dfrac{13225}{10000}} \bigg) - 1 \Bigg]}}}

\quad{: \implies{\sf{1290 =  \Bigg[P  \bigg({1.3225 - 1} \bigg) \Bigg]}}}

\quad{: \implies{\sf{1290 =  P  \times  {0.3225}}}}

\quad{: \implies{\sf{\dfrac{1290}{0.3225}  =  P}}}

\quad{: \implies{\sf{\dfrac{1290 \times 1000}{0.3225 \times 1000}  =  P}}}

\quad{: \implies{\sf{\dfrac{12900000}{3225}  =  P}}}

\quad{: \implies{\sf{\cancel{\dfrac{12900000}{3225}}  =  P}}}

\quad{: \implies{\sf{Rs.4000  =  P}}}

\quad{\dag{\underline{\boxed{\tt{\blue{Principle} =  \purple{Rs.4000 }}}}}}

\begin{gathered}\end{gathered}

<u>Hence,</u>

The sum (Principle) is Rs.4000.

3 0
3 years ago
Please help me! I’ll mark as brilliant
IrinaVladis [17]

Answer: 30 i believe

Step-by-step explanation:

3 0
3 years ago
1) The graph of g(x) is shown below. Which statement given below is FALSE?
Mnenie [13.5K]
<h3>Answer: Choice D </h3>

=======================================================

Explanation:

Let's go through the answer choices one by one to see which are true, and which are false.

  • Choice A) This is true because as we approach x = 2 from the left hand side, the y values get closer to y = 1 from the top
  • Choice B) This is true. As we get closer to x = 4 on the left side, the blue curve is heading downward forever toward negative infinity. So this is what y is approaching when x approaches 4 from the left side.
  • Choice C) This is true also. The function is continuous at x = -3 due to no gaps or holes at this location, so that means its limit here is equal to the function value.
  • Choice D) This is false. The limit does exist and we find it by approaching x = -4 from either side, and we'll find that the y values are approaching y = -2. In contrast, the limit at x = 2 does not exist because we approach two different y values when we approach x = 2 from the left and right sides (approach x = 2 from the left and you get closer to y = 1; approach x = 2 from the right and you get closer to y = -2). So again, the limit does exist at x = -4; however, the function is not continuous here because its limiting value differs from its function value.
  • Choice E) This is true because the function curve approaches the same y value from either side of x = 6. Therefore, the limit at x = 6 exists.
7 0
3 years ago
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