3 years ago

A rail car moving at 10m/s collides with and connect to another stationary car. What is their final velocity?

Physics

1 answer:

ki77a [65]3 years ago

6 0

Answer:

read this it might help some

When a moving object collides with a stationary object of identical mass, the stationary object encounters the greater collision force. When a moving object collides with a stationary object of identical mass, the stationary object encounters the greater momentum change.

Explanation:

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If riding a lawnmower engine exerts 19 hp in one minute to move the lawnmower how much work is done

ioda

Answer:

the work done by the lawnmower is 236.14 J.

Explanation:

Given;

power exerted by the lawnmower engine, P = 19 hp

time in which the power was exerted, t = 1 minute = 60 s.

1 hp = 745.7 watts

The work done by the lawnmower is calculated as follows;

$Work = Energy = \frac{Power}{time} \\\\Work = \frac{(19 \times 745.7)}{60} = 236.14 \ J$

Therefore, the work done by the lawnmower is 236.14 J.

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3 years ago

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Answer:

Gravity, Friction, Air resistance, magnetism, static electricity

Explanation:

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It's Decrease or cease to exist, but I'm leaning more towards decrease.

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3 years ago

A main difference between gravitational and electric forces is that electrical forcesA. attract. B. repel or attract. C. obey th

Nadusha1986 [10]

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repel or attract- B.

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3 years ago

One mole of a gas is placed in a closed system with a 20 L vessel initially at T = 300 K. The vessel is then isothermally expand

Elden [556K]

Answer:

Given that

P = RT/V + a/V²

We know that

H= U + PV

For T= Constant (ΔU=0)

ΔH= ΔU +Δ( PV)

ΔH= Δ( PV)

P = RT/V + a/V²

P V= RT + a/V

dH/dV = d(RT + a/V)/dV

dH/dV = - a/V²

So the expression of dH/dV

$\dfrac{dH}{dV}=\dfrac{-a}{V^2}$

In isothermal process

$\Delta H=nRT\ln{\dfrac{V_2}{V_1}}$ (ΔU=0)

Now by putting the all values

$\Delta H=nRT\ln{\dfrac{V_2}{V_1}}$

$\Delta H=1\times 0.08206\times 300\ln{\dfrac{40}{20}}$

ΔH = 17.06 L.atm

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3 years ago