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egoroff_w [7]
2 years ago
5

2 types of energy transformations that take place in a race car during a race?​

Physics
1 answer:
vichka [17]2 years ago
4 0

Answer:

Explanation:

Chemical to thermal as fuel is burned

Thermal to kinetic as the hot gasses push on pistons

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Throwing a football is an example of force because
siniylev [52]

Answer:

i found this provided by the San Francisco 49ers (found on Khan Academy)

Explanation:

I HOPE THIS HELPS!!!

So, what is a force? A force is a push or a pull exerted on one object from another. Forces make things move. You can make something start or stop when you push or pull an object.

There are many different types of forces in action in football. A player kicking a football is a force that makes the football fly through the air. A quarterback throwing a football is another example of a force that makes the football fly in a game.

When studying the concept of force, we can look to history to find mathematical principles that guide the laws of motion. Sir Isaac Newton was one of the most famous scientists of the 17th century to study the laws of forces and motion. Through careful study of how objects react to various forces, Newton developed the Three Laws of Motion. Below are explanations of each law and how these laws can be applied to football.

4 0
3 years ago
We start with 5.00 moles of an ideal monatomic gas with an initial temperature of 128 ∘C. The gas expands and, in the process, a
o-na [289]

Answer:

The final temperature of the gas is <em>114.53°C</em>.

Explanation:

Firstly, we calculate the change in internal energy, ΔU from the first law of thermodynamics:

ΔU=Q - W

ΔU = 1180 J - 2020 J = -840 J

Secondly, from the ideal gas law, we calculate the final temperature of the gas, using the change in internal energy:

ΔU=\frac{3}{2} nRΔT

ΔU=\frac{3}{2} nR(T_{2} -T_{1} )

Then we make the final temperature, T₂, subject of the formula:

T_{2} =\frac{2ΔU}{3nR} +T_{1}

T_{2} =\frac{2(-840J)}{(3)(5)(8.314J/mol.K)} +128 deg.C

T_{2} =114.53 deg.C

Therefore the final temperature of the gas, T₂, is 114.53°C.

7 0
3 years ago
Compare physical changes and chemical changes
JulijaS [17]

Answer:

The difference between a physical reaction and a chemical reaction is composition. In a chemical reaction, there is a change in the composition of the substances in question; in a physical change there is a difference in the appearance, smell, or simple display of a sample of matter without a change in composition. Although we call them physical "reactions," no reaction is actually occurring. In order for a reaction to take place, there must be a change in the elemental composition of the substance in question. Thus, we shall simply refer to physical "reactions" as physical changes from now on.

Explanation:

Physical changes are limited to changes that result in a difference in display without changing the composition. Some common changes (but not limited to) are:

Texture

Color

Temperature

Shape

Change of State (Boiling Point and Melting Point are significant factors in determining this change.)

Physical properties include many other aspects of a substance. The following are (but not limited to) physical properties.

Luster

Malleability

Ability to be drawn into a thin wire

Density

Viscosity

Solubility

Mass

Volume

4 0
2 years ago
What happens if sulfur forms an ionic bond with another element
bija089 [108]

Answer:

The sulfur will accept the electrons

Explanation:

8 0
3 years ago
When an automobile moves with constant velocity, the power developed is used to overcome the frictional forces exerted by the ai
geniusboy [140]

Answer:

The total frictional force is 358.0 newtons

Explanation:

Power is the amount of average work (W) an object does on a period of time (Δt):

P=\frac{W}{\Delta t}

Remember average work is average force (F) times displacement (Δs):

P=\frac{F \Delta s}{\Delta t}

but displacement over time is average speed v=\frac{\Delta s}{\Delta t}, then:

P=Fv (1)

That is, the power of the car is the force the engine does times the speed of the car. As the question states, if the car is at constant velocity then the power developed is used to overcome the frictional forces exerted by the air and the road, that is by Newton's first law, the force the motor of the car does is equal the force of frictional forces. So, to find the frictional forces we only have to solve (1) for F:

F=\frac{P}{v}

Knowing that 1hp is 746W then 30hp=22380W and 1 mile = 1609m then 140 mph = 225308\frac{m}{h} = 62.5 \frac{m}{s}, then:

F=\frac{22380}{62.5}=358.0 N

6 0
3 years ago
Read 2 more answers
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