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VikaD [51]
3 years ago
15

What would be the volume of a liquid that has a density of 1.2 g/mL and a mass of 24 grams

Physics
1 answer:
Gelneren [198K]3 years ago
8 0

Answer:

<h3>The answer is 20 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question

mass = 24 g

density = 1.2 g/mL

We have

volume =  \frac{24}{1.2}  \\

We have the final answer as

<h3>20 mL</h3>

Hope this helps you

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Missing question in the text:
"A.What are the magnitude and direction of the electric field at the point in question?

B.<span>What would be the magnitude and direction of the force acting on a proton placed at this same point in the electric field?"</span>

<span>Solution:

A) A charge q </span>under an electric field of intensity E will experience a force F  equal to:

F=qE

In our problem we have q=-2.5 nC=-2.5\cdot 10^{-9} C and F=18 nN = 18 \cdot 10^{-9} N, so we can find the magnitude of the electric field:

E= \frac{F}{q}= \frac{18\cdot 10^{-9}N}{2.5\cdot 10^{-9}C}=7.2 V/m

The charge is negative, therefore it moves against the direction of the field lines. If the force is pushing down the charge, then the electric field lines go upward.

B) The proton charge is equal to

e=1.6\cdot 10^{-19} C

Therefore, the magnitude of the force acting on the proton will be

F=eE=1.6\cdot 10^{-19} C \cdot 7.2 V/m=1.15 \cdot 10^{-18} N

And since the proton has positive charge, the verse of the force is the same as the verse of the field, so upward.

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Use the equation of motion to answer the question. Use the equation of motion to answer the question.
satela [25.4K]

The final position of the object after 2 s is 11 m.

Motion: This can be defined as the change in position of a body.

⇒ Formula:

  • x = x₀+v₀t+1/2(at²)........................ Equation 1

⇒ Where:

  • x = Final position of the object
  • x₀ = Starting position
  • v₀ = Starting velocity
  • t = time
  • a = acceleration

From the question,

⇒ Given:

  • x₀ = 4.5 m/s
  • t = 2 s
  • x₀ = 2m
  • a = 0 m/s²

⇒ Substitute these values into equation 1

  • x = 2+(4.5×2)+1/2(0²×2)
  • x = 2+9+0
  • x = 11 m

Hence, The final position of the object after 2 s is 11 m

Learn more about motion here: brainly.com/question/15531840

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