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olga nikolaevna [1]
3 years ago
7

Astronomical observatories have been available since ancient times, and many cultures set aside special sites for astronomical o

bservations. The thing modern observatories have that was missing from these older observatories until about 1610 was:_______________.
Physics
1 answer:
inysia [295]3 years ago
6 0

Answer:

Telescope

Explanation:

Telescope is usually defined as an optical instrument that is commonly used to observe the objects in a magnified way that are located at a large distance from earth. These telescopes are comprised of lenses and curved mirrors that are needed to be arranged in a proper way in order to have a prominent look. It is commonly used by the astronomers.

This was first constructed by Hans Lippershey in the year 1608.

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A 50 g mass is freely hanging from a horizontal meter stick at a distance of 99 cm from the pivot. Calculate the weight force W
Neko [114]

Answer:

W = 0.49 N

τ = 0.4851 Nm

Force

Explanation:

The weight force can be found as:

W = mg

W = (0.05 kg)(9.8 m/s²)

<u>W = 0.49 N</u>

The torque about the pivot can be found as:

τ = W*d

where,

τ = torque

d = distance between weight and pivot = 99 cm = 0.99 m

Therefore,

τ = (0.49 N)(0.99 m)

<u>τ = 0.4851 Nm</u>

The pivot exerts a  <u>FORCE </u>on the meter stick because the pivot applies force normally over the stick and has a zero distance from stick.

6 0
3 years ago
Estimate the wavelength of electrons that have been accelerated from rest through a potential difference of 60 kV.
ivolga24 [154]

Answer: 2.068*10^{-14}m

Explanation: According to work energy-theorem , the workdone in accelerating the electron equals the energy it would give off in terms of light.

workdone= qV

energy = hc/λ

q=magnitude of an electronic charge= 1.602*10^{-16}

h= planck constant = 6.626*10^{-34}

c= speed of light =2.998* 10^{8}

v= potential difference= 6*10^{4}

λ= wavelength=unknown

by making λ subject of formulae we have that

λ= \frac{hc}{qv}

λ = 6.626*10^{-34} * 2.998* 10^{8} / 1.602*10^{-16} * 6*10^{4}

λ = \frac{19.878*10^{-26} }{9.612*10^{-12} }

by doing the necessary calculations, we have that

λ = 2.068*10^{-14}m

8 0
3 years ago
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