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Luden [163]
3 years ago
11

you can produce a sound by plucking a string or by blowing in a pipe. how are these two ways different?​

Physics
1 answer:
Shkiper50 [21]3 years ago
4 0

Answer:

a differenceis that the string needs force to be used. without something pulling on it then it wont make the noise. meanwhile the pipe only needs air to be blow Wich can be caused naturally or intentionally

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Newtons prism experiments showed that white sunlight is made up of
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All the colors of the visible spectrum
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A vibrating pendulum makes 20 complete vibrations in 12.2 seconds. Determine the vibrational period of the pendulum, along with
Hitman42 [59]

Answer:

And the same can be said of a pendulum vibrating about a fixed position or of a guitar ... along the time axis, it is possible to determine the time for one complete cycle. ... It takes 2.3 seconds to complete the first full cycle of vibration. ... Since the standard metric unit of time is the second, frequency has units of cycles/second.

Explanation:

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4 0
3 years ago
A car is traveling at a speed of 20m/s and has a mass of 1200kg how much kinetic energy does it have
Oxana [17]

Answer:

Explanation:

The formula for Kinetic Energy is

KE=\frac{1}{2}mv^2. Filling in:

KE=\frac{1}{2}(1200)(20)^2 It looks like we only need 1 significant digit here but I'll give you 2 and you can round how you want.

KE = 2.4 × 10⁵ J

4 0
3 years ago
When a light ray passes from LESS dense water (n = 1.33) into a MORE dense diamond (n = 2.419) at an angle of 45 degrees, its pa
Ivenika [448]

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<u>Explanation:</u>

When light is incident at a transparent surface, the transmitted component of the light changes direction at the interface. Another component of the light is reflected at the surface. When a ray of light passes from water to diamond at an angle 45°, its path is bent towards the normal. This is so because water is less dense than the diamond. The refractive index of water (n = 1.33) is less than the refractive index of diamond (n = 2.419).

3 0
3 years ago
If the potential due to a point charge is 490 V at a distance of 10 m, what are the sign and magnitude of the charge?
uysha [10]

Answer:

+5.4×10⁻⁷ C

Explanation:

Electric potential: This can be defined as the work done in bringing a unit charge from infinity to that point against the action of the field. The S.I unit of potential is volt (V)

The formula for potential is

V = kq/r............................ Equation 1

Where V = electric potential, k = proportionality constant, q = charge, r = distance.

making q the subject of the equation,

q = Vr/k............................ Equation 2

Given: V = 490 V, r = 10 m,

Constant: k = 9×10⁹ Nm²/C²

Substitute into equation 2

q = 490(10)/(9×10⁹)

q = 5.4×10⁻⁷ C

q = +5.4×10⁻⁷ C

Hence the charge is +5.4×10⁻⁷ C

7 0
3 years ago
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