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tekilochka [14]
3 years ago
11

A circuit contains two 1.5 volt battery and a bulb with a resistance of 3 ohms. Calculate the current

Physics
1 answer:
horrorfan [7]3 years ago
3 0

Answer:

<em>The current is 1 A</em>

Explanation:

<u>Current in a Series Connection </u>

When two or more elements are connected in series, all of them have the same current, and the sum of their individual voltages is the total voltage applied to the circuit.

According to Ohm's law:

V=R.I

Where V is the voltage, R is the resistance and I is the current of a circuit.

We have a voltage of V=1.5 V + 1.5 V = 3 V and a resistance of R=3 ohms.

We can calculate the current by solving for I:

\displaystyle I=\frac{V}{R}=\frac{3}{3}=1\ A

The current is 1 A

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K_f is the final kinetic energy, at the bottom

By explicing the potential energy, we can rewrite the equation as:

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where:

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The initial kinetic energy is zero, since the ball starts from rest:

K_i = 0

Therefore we can solve the equation for K_f, the final kinetic energy of the ball:

K_f = mg(h_i-h_f)=(0.5)(9.8)(2-1.50)=2.45 J

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