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3 years ago

What element is a gas at room temp, has 6 valence electrons, and is non-reactive

Chemistry

1 answer:

sveta [45]3 years ago

7 0

Answer:

Noble gases

Explanation:

Noble gases are nonreactive, nonmetallic elements in group 18 of the periodic table. As you can see in the periodic table in the figure below, noble gases include helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn).18 Jun 2021

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Aleks04 [339]

Answer:

It results from microscopic bumps and ridges

It causes a change in motion

It is opposite to the direction of the motion.

It is parallel to the surfaces that rub together.

Explanation:

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3 years ago

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When did ernest rutherford contribute to the atomic theory?

charle [14.2K]

In 1911, Rutherford performed experiment to determine the structure on atom

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4 years ago

. One mole of N2O4 contains ___________.

ivanzaharov [21]

One molecule of N2O4 contains

two nitrogen
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3 years ago

The ΔHvap of a certain compound is 49.09 kJ·mol–1 and its ΔSvap is 53.69 J·mol–1·K–1. What is the boiling point of this compound

rusak2 [61]

Hey there !

Convert Joule to KJ :

1 j ---------------- 0.001 kj
53.69 j ----------- Kj

Kj = 53.69 * 0.001

=> 0.05369 Kj

T = ΔH / ΔS

T = 49.09 / 0.05369

T = 914.32ºC

3 0

3 years ago

The photodissociation of ozone by ultraviolet light in the upper atmosphere is a first-order reaction with a rate constant of 1.

atroni [7]

Answer:

[O₃]= 8.84x10⁻⁷M

Explanation:

The photodissociation of ozone by UV light is given by:

O₃ + hν → O₂ + O (1)

The first-order reaction of the equation (1) is:

$rate = k [O_{3}] = - k \frac{\Delta [O_{3}]}{\Delta t}$ (2)

where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration

We can get the following expression of the first-order integrated law of the reaction (1), by resolving the equation (2):

$[O_{3}]_{t} = [O_{3}]_{0} \cdot e^{-kt}$ (3)

where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration

We can calculate the initial ozone concentration using equation (3):

$[O_{3}]_{t} = 5.0 \cdot 10^{-3}M \cdot e^{-(1.0\cdot 10^{-5}s^{-1}) (\frac{10d \cdot 24h \cdot 3600 s}{1d \cdot 1h})} = 8.84 \cdot 10^{-7}M$

So, the ozone concentration after 10 days is 8.84x10⁻⁷M.

I hope it helps you!

3 0

4 years ago