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Anna [14]
2 years ago
10

1. What would happen if you aimed light from the magenta part of the Horsehead Nebula through a spectrograph?

Chemistry
1 answer:
otez555 [7]2 years ago
4 0

Given what we know, we can confirm that if you aimed light from the magenta part of the Horsehead Nebula through a spectrograph we would be able to determine more precisely the structure and details of the cloud.

<h3>How do we use Spectrums in order to understand stars?</h3>

The spectrums recorded by scientists, such as those of stars or nebulas like the horsehead nebula can tell us a great deal about the composition of said entities. Studying the spectrum can tell scientists about the chemical composition of stars or nebulas, such as information about the elements that form them, like their temperatures and densities.

<h3 /><h3>How would a discontinuous emission of hydrogen gas look in the spectrum?</h3>

This would appear as pauses in the lines of the spectrum. If the emission of the hydrogen gas were constant, there would be a continuous line on the spectrum graph to indicate the illuminated hydrogen, though if this line were discontinuous, we would be able to assume that its source is emission from another gas instead.

Therefore, we can confirm that spectrography is an essential part of scientific discovery pertaining to our universe. It allows us to study the chemical composition of stars and nebulas, and determine the sources of certain emissions like that of hydrogen gases.

To learn more about spectrographs visit:

brainly.com/question/15290407?referrer=searchResults

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Answer:

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the volume of a gas is 550 ml at 960 mm hg and 200.0°C. What volume would the pressure of the gas be 830 mm Hg if the temperatur
gavmur [86]

Answer:

V₂ = 568.9 mL

Explanation:

Given data:

Volume of gas = 550 mL

Pressure of a gas = 960 mmHg

Temperature = 200.0°C ( 200+273 = 473 K)

Final volume = ?

Final pressure = 830 mmHg

Final temperature = 150°C (150+273 = 423 K)

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 960 mmHg × 550 mL × 423 K / 473 K ×830 mmHg

V₂ = 223344000 mL / 392590

V₂ = 568.9 mL

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