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patriot [66]
3 years ago
8

6) (a) Calculate the absorbance of the solution if its concentration is 0.0278 M and its molar extinction coefficient is 35.9 L/

(mol cm). The depth of the cell is 5 mm. (b) What is the %T? (7) Calculate the absorbance of the solution if the transmitted light intensity is 70% of the initial light beam intensity
Chemistry
1 answer:
Anvisha [2.4K]3 years ago
8 0

Answer:

6) (a) 0.499; (b) 31.7 %

7) 0.15

Explanation:

6) (a) Absorbance

Beer's Law is

A = \epsilon cl\\A = \text{35.9 L&\cdot$mol$^{-1}$cm$^{-1}$} $\times$ 0.0278 mol$\cdot$L$^{-1} \times $ 0.5 cm = \mathbf{0.499}

(b) Percent transmission

A = \log {\left (\dfrac{1}{T}}\right)}\\\\\%T = 100T\\\\T = \dfrac{\%T}{100}\\\\\dfrac{1}{T} = \dfrac{100 }{\%T}\\\\A = \log \left(\dfrac{100 }{\%T} \right ) = 2 - \log \%T\\\\0.499 = 2 - \log \%T\\\\\log \%T = 2 - 0.499 = 1.501\\\\\%T = 10^{1.501} = \mathbf{31.7}

7) Absorbance

A = \log \left (\dfrac{I_{0}}{I} \right ) = \log \left (\dfrac{I_{0}}{0.70I_{0}} \right ) = \log \left (\dfrac{1}{0.70} \right ) = -\log(0.70) = \mathbf{0.15}}

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5 0
2 years ago
Ethanol, C2H6O, is most often blended with gasoline - usually as a 10 percent mix - to create a fuel called gasohol. Ethanol is
ch4aika [34]

Answer:

4054 kcal of heat is released during complete combustion of 354 g of octane.

Explanation:

Heat of combustion of 1 mol of octane is 1.308\times 10^{3} kcal

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We know, no. of moles = (mass)/(molar mass)

So, 1.308\times 10^{3} kcal of heat is released during complete combustion of 114.23 g of octane.

So, amount of heat is released during complete combustion of 354 g of octane = (\frac{1.308\times 10^{3}}{114.23})\times 354  kcal = 4054 kcal

Hence 4054 kcal of heat is released during complete combustion of 354 g of octane.

5 0
2 years ago
An electrochemical cell is constructed such that on one side a pure lead electrode is in contact with a solution containing Pb2+
Ugo [173]

Answer:

-490.7 K

Explanation:

Given:

[Ni^2+]= 0.4 M

[Pb^2+]=0.002 M

∆V= -0.012 V

VNi= -0.250V

VPb= -0.126V

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R= 8.314 JK-1 mol-1

n= 2

From

T= -nF/R [∆V-(VNi-VPb)/ln [Pb2+]/[Ni2+]]

T= 2(96500)/8.314[ (-0.012) -(-0.250) - (-0.126))/ln[0.002]/[0.4]

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4 0
3 years ago
What type of energy is stored in the earths crust and produces earthquakes
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A rapid release of stored up energy 
8 0
3 years ago
Read 2 more answers
Arrange the following ions in order of increasing ionic radius.
Zepler [3.9K]

Answer:

Ca 2+ <K  +  <Ar<Cl  −  <S  2−

Explanation:

Ar,K  + ,Cl  − ,S  2− ,Ca  2+

 have the same number of electrons. Their radii would be different because of their different nuclear charges. The cation with the greater positive charge will have a smaller radius because of the greater attraction of the electrons to the nucleus. Anion with the greater negative charge will have the larger radius. In this case, the net repulsion of the electrons will outweigh the nuclear charge and the ion will expand in size. Hence the correct order will be Ca  

2+  <K +  <Ar<Cl  −  <S  2−

 

3 0
2 years ago
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