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Whitepunk [10]
4 years ago
13

BRAINLIEST ANSWER _ A balloon occupies a volume of 0.93 liters at a pressure of 84.5 kPa. When the balloon is allowed to expand

so that it occupies one full liter (the temperature is held constant), what is the pressure of the air inside of the balloon?
Chemistry
1 answer:
SVEN [57.7K]4 years ago
5 0
V1 = 2.0 L T1 = 25.0 oC = 298 K V2 = V1T2 = (2.0 L)(244 K) = 1.6 L V2 = ? t1(298 K) T2 = –28.9 oC = 244 K
 
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Which of the following is an ionic compound? <br> CCl4<br> NO<br> Al2O3<br> P2S5
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Is there a mathematical pattern in the number of
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4 0
3 years ago
A solution is prepared by dissolving 27.0 g of urea [(NH2)2CO], in 150.0 g of water. Calculate the boiling point of the solution
andrew11 [14]

<u>Answer:</u> The boiling point of solution is 101.56°C

<u>Explanation:</u>

Elevation in boiling point is defined as the difference in the boiling point of solution and boiling point of pure solution.

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Boiling point of pure water = 100°C

i = Vant hoff factor = 1 (For non-electrolytes)

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m_{solute} = Given mass of solute (urea) = 27.0 g

M_{solute} = Molar mass of solute (urea) = 60 g/mol

W_{solvent} = Mass of solvent (water) = 150.0 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=1\times 0.52^oC/m\times \frac{27\times 1000}{60\times 150}\\\\\text{Boiling point of solution}=101.56^oC

Hence, the boiling point of solution is 101.56°C

5 0
4 years ago
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