Y = 5x - 8<br><br> 4x + 3y = 33 el valor de x es ?

Answer my questions plz help

coldgirl [10]

9514 1404 393

Answer:

a = -2/3, b = 8, c = -24
y-intercept: (0, -24)
x = -b/(2a) = -8/(2(-2/3)) = 8(4/3)
x = 6
DOWN
Max: (6, 0)
Vertex: (6, 0)
Domain: {x | x ∈ ℝ}
Range: {x | x ≤ 0}

Step-by-step explanation:

To find a, b, c, compare the given function to ...

f(x) = ax² +bx +c

You will see that ...

a = -2/3
b = 8
c = -24

The y-intercept is the function value for x=0. It is the constant term:

y-intercept = f(0) = -24

Use the above values of a, b to find the line of symmetry.

$x = \dfrac{-b}{2a}=\dfrac{-8}{2\cdot\dfrac{-2}{3}}=8\cdot\dfrac{3}{4}=6$

Per the calculation, the line of symmetry is ...

x = 6

The negative leading coefficient tells you the parabola opens DOWN.

Because it opens down, the vertex at (6, 0) is a Maximum.

As with any polynomial, the domain is "all real numbers", hence any x that is an element of Reals.

The range is all values below the vertex (including the vertex), so is ...

x ≤ 0

3 0

2 years ago

Find the surface area of the pyramid shown to the nearest whole number.

Snezhnost [94]

Answer:

<h3>The answer is option A</h3>

Step-by-step explanation:

Surface area of a pyramid =

area of base + area of triangular faces

Since it's a square based pyramid

It's surface area is

area of base + 4( area of one triangular face)

Since the square has equal sides

<u>For square base </u>

Area of a square = l²

where l is the length

From the question l = 5

So we have

Area of square base = 5² = 25ft²

<u>For one of the triangular face</u>

Area of a triangle = ½ × base × height

base = 5

height = 6

Area = ½ × 5 × 6 = 15ft²

So the surface area of the pyramid is

25 + 4(15)

= 25 + 60

We have the final answer as

<h3>Surface area = 85 ft²</h3>

Hope this helps you

7 0

2 years ago

Given the three vertices W(−1, 4), X(−3, −2), and Y(3, −4), what are the coordinates of Z that make quadrilateral WXYZ a square?

prohojiy [21]

Answer:

I don't see how the three existing points could ever become a square with the addition of a foiurth point.

Step-by-step explanation:

See the attached image.

A square would require that all angles be 90 degrees. The given points are the top three points on the graph. If we enter the two equations that intersect these points (blue and black lines), we can see that the angle on top is not 90 degrees. I can't see that this could ever be a square with a fourth point, z. I did find a value for z that make the four points a parallelogram.