It would be the 2nd one because the higher the farther away from the equator. <span />
Answer:
![y_{4}-y_{3}=35.22-11.27=23.95 \mathrm{cm}](https://tex.z-dn.net/?f=y_%7B4%7D-y_%7B3%7D%3D35.22-11.27%3D23.95%20%5Cmathrm%7Bcm%7D)
Explanation:
Given that
Wavelength
slit separation
slit screen distance
We know that for double slit the maxima condition is that
For small angle approximation,
Now
Again
Hence ![y_{4}-y_{3}=35.22-11.27=23.95 \mathrm{cm}](https://tex.z-dn.net/?f=y_%7B4%7D-y_%7B3%7D%3D35.22-11.27%3D23.95%20%5Cmathrm%7Bcm%7D)
Answer:
d = 68.18 m
Explanation:
Given that,
Initial velocity, u = 15 m/s
Finally it comes to stop, v = 0
Acceleration, a = -1.65 m/s²
Time, t = 2.5 s
We need to find the distance covered by the hayride before coming to a stop. Let d is the distance covered. Using third equation of motion to find it :
![v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{-(15)^2}{2\times -1.65}\\\\d=68.18\ m](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2ad%5C%5C%5C%5Cd%3D%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2a%7D%5C%5C%5C%5Cd%3D%5Cdfrac%7B-%2815%29%5E2%7D%7B2%5Ctimes%20-1.65%7D%5C%5C%5C%5Cd%3D68.18%5C%20m)
So, the hayride will cover a distance of 68.18 m.
Answer
graph 2
Explanation
Velocity is the rate of change of displacement.
Velocity = (change in displacement)/(change is time)
In graph 2, the gradient of the curve is positive, indicating that the velocity is positive.
Acceleration is the rate of change of velocity.
The steepness of the slope of the same graph (graph 2) is decreasing. This shows that the velocity is decreasing hence a negative acceleration.