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frozen [14]
4 years ago
5

A hayride wagon is going down a spooky country road at 15 m/s when a Scarecrow appears in the roadway. The man at the wheel of t

he tractor takes 2.5 seconds to react and applies the breaks at a -1.65 m/s/s coming to a stop. How far did the hayride move before coming to a stop?
Physics
1 answer:
nexus9112 [7]4 years ago
6 0

Answer:

d = 68.18 m

Explanation:

Given that,

Initial velocity, u = 15 m/s

Finally it comes to stop, v = 0

Acceleration, a = -1.65 m/s²

Time, t = 2.5 s

We need to find the distance covered by the hayride before coming to a stop. Let d is the distance covered. Using third equation of motion to find it :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{-(15)^2}{2\times -1.65}\\\\d=68.18\ m

So, the hayride will cover a distance of 68.18 m.

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A stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. What is the spe
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Answer: V = 15 m/s

Explanation:

As  stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,

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Using doppler effect formula

F = C/ ( C - V) × f

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Substitute all the parameters into the formula

2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10

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1.000000049 = 3×10^8/(3×10^8 - V)

Cross multiply

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Collect the like terms

1.000000049V = 14.71429

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