Answer: 24.5 cm
Explanation:
Given
Force constant of spring, k = 40 N/m
Diameter of spring, d = 5.1 cm = 0.051 m
Mass of cylinder, m = 1.5 kg
Let us assume that the cylinder is hanging in such a way that the circular end is parallel with the water. Also, we assume that the tank water level is not materially affected by the displacement of the cylinder while the cylinder sinks. The water is fresh and as we all know, the density of water is 1000 kg/m³
To solve this, we assume x to be the spring extension and it's equivalent sinking distance(in meters). We then apply the formula,
mg = kx + ρgAx
mg = x(k + ρgA)
x = mg / (k + ρgA), where
A = πd²/4
A = (3.142 * 0.051²)/4
A = 0.0082 / 4
A = 0.00205 m²
x = 1.5 * 9.81 / [40 + (1000 * 9.81 * 0.00205)]
x = 14.715 / (40 + 20.1105)
x = 14.715 / 60.1105
x = 0.245 m
or 24.5 cm of stretch or sinking
Answer:
2880 N/c
Explanation:
Given that:
Charge per unit length ; λ = 4 * 10^-9
radius, r = 10
Radius, R = 0.5m
Using the relation :
2λr / 4πE0R²
Columb's constant, k = 1/4πE0 =. 9* 10^9Nm²/C²
Hence, we have :
2λrk/ R²
(2 * 4 * 10^-9 * 10 * 9 * 10^9) / 0.5^2
(720 ÷ 0.25)
= 2880 N/c
Answer:
440J
Explanation:
First, let us find the <u>weight </u>of the barbell.
The formula to find the weight is :
W = m × g
Here,
m ⇒ mass ⇒ 20 kg
g ⇒ acceleration of gravity
<u>Let us find it now.</u>
W = m × g
W = 20 kg × 10 ms⁻²
W = 200N
And now let us find<u> the work done by this weight lifter.</u>
Work = Force × Displacement
<u>Let us find it now.</u>
Work = Force × Displacement
= 200N × 2.2m
=<u> 440J</u>
Hello! The 7 inches on a blueprint represents the actual length of 38.5 feet. To find the scale on the blueprint, let's divide the actual length by the amount of inches on the blue print. 38.5 / 7 is 5.5. There. 1 in = 5.5 ft.
D. you develop positive interactions with your peers