*Earth Science Question*

Kevin works for his own gutter and siding company and loves that he gets to climb around and work outside. marsha is an accounta

Colt1911 [192]

I have worked in both situations, and I understand each
of their preferences.

I hope both Kevin and Marsha are successful at their jobs,
and may they live long and prosper.

Thank you for sharing their heartwarming stories.

7 0

3 years ago

A loop of wire is placed in a uniform magnetic field. Let ø be the angle between the direction of b and the normal. At which val

zaharov [31]

Answer:

B. 0 degrees

Explanation:

The magnetic flux through a certain area enclosed by a loop of wire immersed in a region with magnetic field is given by:

$\Phi = B A cos \theta$

where

B is the strength of the magnetic field

A is the area enclosed by the coil

$\theta$ is the angle between the direction of the magnetic field and the direction of the normal to the coil

From the equation above, we see that the magnetic flux is maximum when

$cos \theta=1$

So when the field is parallel to the normal to the coil (so, when it is perpendicular to the coil), therefore when:

$\theta=0^{\circ}$

So, the correct option is

B. 0 degrees

5 0

4 years ago

Which one of the following accurately describes the force of gravity? A. The force of gravity is slightly lower at the bottom of

AfilCa [17]

Choice ' C ' is a correct statement.
The other choices aren't.

6 0

4 years ago

I shared a picture of the problem. It’s a basic Physics question and an Algebra question.

julia-pushkina [17]

Hence the expression of ω in terms of m and k is

$\omega = \sqrt{\frac{k}{m}$

Given the expressions;

$T_s = 2 \pi \sqrt{\frac{m}{k} } \ and \ T_s = \frac{2 \pi}{\omega}$

Equating both expressions we will have;

$2 \pi \sqrt{\frac{m}{k} } = \frac{2 \pi}{\omega}$

Divide both equations by 2π

$\frac{2 \pi\sqrt{\frac{m}{2 \pi} } }{2 \pi}=\frac{\frac{2 \pi}{\omega} }{2\pi}\\\sqrt{\frac{m}{2 \pi} } = \frac{1}{\omega}\\$

Square both sides

$(\sqrt{\frac{m}{k} } )^2 = (\frac{1}{\omega} )^2\\\frac{m}{k} = \frac{1}{\omega ^2} \\\omega ^2 = \frac{k}{m}$

Take the square root of both sides

$\sqrt{\omega ^2} =\sqrt{\frac{k}{m} } \\\omega = \sqrt{\frac{k}{m}$

Hence the expression of ω in terms of m and k is

$\omega = \sqrt{\frac{k}{m}$

3 0

3 years ago

I need friends so if you want to be my friend let me know

nydimaria [60]

Answer:

sure if I can figure out how to follow you

Explanation:

recenty joined

3 0

2 years ago