<h3>Newtons first law state that if a body is in motion it will be in motion and if a body is in rest it will tend to be in rest. This phenomena is also called INERTIA. Example: We tend to fall sideways when a car turn suddenly</h3>

5 0

2 years ago

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Lake point tower in chicago is the tallest apartment building in the united states. suppose you take the elevator from street le

notka56 [123]

Using the idea of work done under gravity, the height of the building is 187 m.

<h3>Work done in a gravitational field</h3>

We must recall that the work done in a gravitational field is given by; mgh

m= mass

g = acceleration due to gravity

h = height

mass = 60.0 kg

Workdone = 1.15x10^5 J

W = mgh

h = W/mg

h = 1.15x10^5 J/60.0 kg * 9.8 ms-2

h = 187 m

Learn more about work done: brainly.com/question/13662169?

7 0

1 year ago

A 6.60-kg block slides with an initial speed of 1.56 m/s up a ramp inclined at an angle of 28.4° with the horizontal. The coeffi

Vlad [161]

Answer:

The distance travel by block before coming to rest is 0.122 m

Explanation:

Given:

Mass of block $m = 6.60$ kg

Initial speed of block $v _{i} = 1.56$ $\frac{m}{s}$

Final speed of block $v_{f} = 0$ $\frac{m}{s}$

Coefficient of kinetic friction $\mu _{k} = 0.62$

Ramp inclined at angle $\theta =$ 28.4°

Using conservation of energy,

Work done by frictional force is equal to change in energy,

$\mu _{k} mgd \cos 28.4 = \Delta K - \Delta U$

Where $\Delta U = mg d\sin 28.4$

$\mu _{k} mgd \cos 28.4 = \frac{1}{2}mv_{i} ^{2} - mgd\sin 28.4$

$\mu _{k} mgd \cos 28.4 +mgd\sin 28.4 = \frac{1}{2}mv_{i} ^{2}$

$d(6.60 \times 9.8 \times 0.62 \times 0.879 + 6.60 \times 9.8 \times 0.475) = \frac{1}{2} \times 6.60 \times (1.56)^{2}$

$d = 0.122$ m

Therefore, the distance travel by block before coming to rest is 0.122 m

7 0

3 years ago

A cat pushes a porcelain statue off a bookshelf with a speed of 0.5 m/s and it smashed on the floor 0.85 sec later.

Bad White [126]

Answer:

167?

Explanation:

i added both

5 0

2 years ago