How much voltage is required to run 0.025 A of current through a 36 Ω resistor?
1 answer:
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Explanation:
Let us assume that the separation of plate be equal to d and the area of plates is . As the capacitance of capacitor is given as follows.
C =
It is known that the dielectric strength of air is as follows.
E =
Expression for maximum potential difference is that the capacitor can with stand is as follows.
dV = E × d
And, maximum charge that can be placed on the capacitor is as follows.
Q = CV
=
=
=
=
or, = 10.62 nC
Thus, we can conclude that charge on capacitor is 10.62 nC.
K.E = 1/2mv^2
The kinetic energy is 50,000 J and the mass of the car is 10,000 kg.
50,000 J = 1/2(10,000kg)v^2
Solve for v (velocity)
50,000 J = 5,000 kg x v^2
10 = v^2
about 3 m/s (in terms of significant figures)
The kinetic energy is 50,000 J and the mass of the car is 10,000 kg.
50,000 J = 1/2(10,000kg)v^2
Solve for v (velocity)
50,000 J = 5,000 kg x v^2
10 = v^2
about 3 m/s (in terms of significant figures)