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sladkih [1.3K]
3 years ago
13

How much voltage is required to run 0.025 A of current through a 36 Ω resistor?

Physics
1 answer:
aalyn [17]3 years ago
7 0

Yes D is definitely the answer

<em>V</em><em>=</em><em>I×</em><em>R</em>

<em>V</em><em>=</em><em>0</em><em>.</em><em>0</em><em>2</em><em>5</em><em>×</em><em>3</em><em>6</em>

<em>V</em><em>=</em><em>0</em><em>.</em><em>9</em><em> </em><em>sa</em><em>me</em><em> </em><em>as</em><em> </em><em>0</em><em>.</em><em>9</em><em>0</em>

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Iron-rich minerals in rock pointed in one direction and then switched to the exact opposite direction. This supports what idea?
NISA [10]
Iron rich minerals in rock pointed in one direction the switch to the exact opposite direction. I'd say that what supports this idea is that Earth's magnetic field goes through pole reversals.<span>
</span>
4 0
3 years ago
Read 2 more answers
A young parent is dragging a 65 kg (640 N) sled (this includes the mass of two kids) across some snow on flat ground, by means o
Delicious77 [7]

Answer:

b) N = 560 N, c)  fr = 138.56 N, d)  μ = 0.247

Explanation:

a) In the attachment we can see the free body diagram of the system

b) Let's write Newton's second law on the y-axis

              N + T_y -W = 0

              N = W -T_y

let's use trigonometry for tension

             sin θ = T_y / T

             cos θ = Tₓ / T

             T_y = T sin θ

             Tₓ = T cos θ

we substitute

              N = W - T sin 30

we calculate

              N = 640 - 160 sin 30

              N = 560 N

c) as the system goes at constant speed the acceleration is zero

X axis

              Tₓ - fr = 0

               Tₓ = fr

we substitute and calculate

              fr = 160 cos 30

              fr = 138.56 N

d) the friction force has the formula

             fr = μ N

             μ = fr / N

we calculate

             μ = 138.56 / 560

             μ = 0.247

4 0
2 years ago
PLEASE HELP URGENT 10 points
melamori03 [73]

Answer:

Both have the same amount. C.

Explanation:

3 0
3 years ago
A 4.50-kg wheel that is 34.5 cm in diametet rotates through an angle of 13.8 rad as it slows down uniformly from 22.0 rad/s to 1
lisabon 2012 [21]

Answer:

\alpha =10.93radian/sec^2

Explanation:

We have given given the final angular velocity \omega _{final}=13.5rad/sec

And \omega _{initial}=22rad/sec

Displacement \Theta =13.8radian

We have to find the angular acceleration \alpha

According to law of motion \omega _{final}^2=\omega _{initial}^2+2\alpha \Theta

So 13.5^2=22^2+2\times \alpha \times 13.8

\alpha =-10.93radian/sec^2

In question we have tell about magnitude only so \alpha =10.93radian/sec^2

4 0
3 years ago
Identify two forms of friction that <br> oppose the motion of a moving car
babymother [125]
Static friction opposes the movement of car from the state of rest.
Dynamic or kinetic friction opposes the movement of the car when car is running at any speed.


8 0
3 years ago
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