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Vanyuwa [196]
3 years ago
5

Atom: Finally, there is the ever-so-tiny atom. It takes extremely powerful microscopes to view

Physics
1 answer:
katovenus [111]3 years ago
6 0
A

That should be correct!!!
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The impulse given to a ball with mass of 2 kg is 16 N*s. If the ball starts from rest, what is its final velocity?
Alik [6]
The impulse is equal to the variation of momentum of the object:
I=\Delta p = m \Delta v
where m is the mass object and \Delta v = v_f - v_i is the variation of velocity of the object.

The ball starts from rest so its initial velocity is zero: v_i=0. So we can rewrite the formula as
I=m v_f
or 
v_f =  \frac{I}{m}

and since we know the impulse given to the ball (I=16 Ns) and its mass (m=2 kg), we can find the final velocity of the ball:
v_f =  \frac{16 Ns}{2 kg}=  8 m/s
7 0
3 years ago
Read 2 more answers
Write five ideas that you can recall about the types of important values and skills, how to set and reach goals, and different w
fenix001 [56]

Answer:

Find the ideas below.

Explanation:

1. Important values are those standards that people live by and which inspires them to act. Some of them include respect, honesty, integrity, and responsibility.

2. Important skills are those learned behaviors that help people to be more productive. There are hard and soft skills. Examples include; communication, teamwork, time management, information technology skills, etc.

3. To set and reach goals, a person must be focused, disciplined, ready to learn from others, and willing to never give up.

4. People learn in different ways and at their own pace.

5. There are four learning styles and these include; auditory, visual, kinesthetic, and reading/writing learners.

3 0
3 years ago
Noah is loading the ark and the last animal on board is a stubborn 1500-kg elephant who refuses to budge. Noah and his family pu
Oxana [17]

The coefficient of sliding friction is 0.514

Explanation:

We start by writing the equations of motion of the elephant along the two directions, parallel and perpendicular, to the incline.

Along the parallel direction we have:

F- mg sin \theta - \mu_k R = ma (1)

where :

F = 10,000 N is the force applied by Noah

mg sin \theta is the component of the weight parallel to the incline, where:

m is the mass

g = 9.8 m/s^2 the acceleration of gravity

\theta=10^{\circ}  is the angle of incline

\mu_k R is the force of friction, where:

\mu_k is the coefficient of friction

R is the normal reaction  

and a is the acceleration

Perpendicular direction:

R-mg cos \theta =0 (2)

where mg cos \theta is the component of the weight perpendicular to the incline

From (2) we find

R=mg cos \theta

And substituting into (1)

F-mg sin \theta - \mu_k mg cos \theta = ma

We know that the elephant moves at constant speed, so the acceleration is zero:

a = 0

So the equation becomes

F-mg sin \theta - \mu_k mg cos \theta=0

And we can re-arrange it to find the coefficient of friction:

F-mg sin \theta - \mu_k mg cos \theta=0\\\mu_k = \frac{F-m g sin \theta}{mg cos \theta}=\frac{10000-(1500)(9.8)(sin 10)}{(1500)(9.8)(cos 10)}=0.514

Learn more about friction and inclined planes:

brainly.com/question/5884009

#LearnwithBrainly

4 0
3 years ago
Do you have to use significant figures in converting temperatures
schepotkina [342]
Not only in converting temperatures I think, we always use significant figures every time we want to make some experimental report using the exact data from our experiment. If that isn't experimental report ( some exercise/questions from your textbook) it's not necessary
4 0
4 years ago
Two spherical conductors are separated by a distance much larger than either of their radii. Sphere A has a radius of 11.5 cm an
bonufazy [111]

Explanation:

As the given spheres are connected by a thin wire so, the potential on the spheres are the same.

          \frac{q_{1}}{r_{1}} = \frac{q_{2}}{r_{2}} ......... (1)

Hence, total charge will be as follows.

              q_{1} + q_{2} = Q = -95.5 nC .......... (2)

Using the above two equations, the final equation will be as follows.

          q_{2} = \frac{Qr_{2}}{r_{1} + r_{2}}

and,    q_{1} = \frac{Qr_{1}}{r_{1} + r_{2}}

Hence, we will calculate the charge on sphere B after the equilibrium is reached as follows.

          q_{2} = \frac{Qr_{2}}{r_{1} + r_{2}}

                     = \frac{-95.5 \times 74.4 cm}{(11.5 + 74.4) cm}

                     = 82.714 nC

Thus, we can conclude that the charge on sphere B after equilibrium has been reached is 82.714 nC.

                       

5 0
3 years ago
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