Let the key is free falling, therefore from equation of motion
.
Take initial velocity, u=0, so
.

As velocity moves with constant velocity of 3.5 m/s, therefore we can use formula

From above substituting t,
.
Now substituting all the given values and g = 9.8 m/s^2, we get
.
Thus, the distance the boat was from the point of impact when the key was released is 10.60 m.
I think it's The fossil record. The same animal fossil is in Africa and South America. The animal could have not swim across so its the fossil record
The velocity of the pitcher at the given mass is 0.1 m/s.
The given parameters:
- <em>Mass of the pitcher, m₁ = 50 kg</em>
- <em>Mass of the baseball, m₂ = 0.15 kg</em>
- <em>Velocity of the ball, u₂ = 35 m/s</em>
<em />
Let the velocity of the pitcher = u₁
Apply the principle of conservation of linear momentum to determine the velocity of the pitcher as shown below;
m₁u₁ = m₂u₂

Thus, the velocity of the pitcher at the given mass is 0.1 m/s.
Learn more about conservation of linear momentum here: brainly.com/question/13589460