Answer:
Explanation:
Using Pascal laws, which states that pressure are the input equals the pressure at the output.
Pressure is given as force/area
P1=P2
Then,
F1/A1=F2/A2
Cross multiply
F1A2=F2A1
Given that
Ae=0.5m² area of effort
Al=5m² area of load
Fl=? Force if load
Fe= 100N. Force of effort
Then applying pascal
Fl/Al=Fe/Ae
Fl/5=100/0.5
FL/5=200
Fl=200×5
Fl=1000N
The first safety load is 1000N
Answer:
The lone pair of electrons occupy more space because the electrostatic force becomes weaker.
Explanation:
When there is a bond pair of electrons in the 2 positively charged the atomic nuclei draw the electron density towards them, thereby reducing the bond diameter.
In the case of the lone pair, only 1 nucleus is present, and the enticing electrostatic force becomes weaker and the intensity of the electrons will be increases. Therefore, the lone pair occupies more space than the pair of bonds.
Answer: The correct answer is "the pitch drops to a lower pitch once the ambulance passes by Juan".
Explanation:
Doppler effect is the phenomenon in which there is an increase or decrease in the frequency when there is relative motion between the source and listener.
Pitch depends on the frequency. if the frequency increases then pitch increases.
When the source and the listener are moving towards each other then there is increase in the frequency. When the source and the listener are moving away each other then there is decrease in the frequency.
In the given problem, Juan is standing on the street. An ambulance moves toward him and then passes by the pitch drops to a lower pitch once the ambulance passes by Juan.
Answer:
4987N
Explanation:
Step 1:
Data obtained from the question include:
Mass (m) = 0.140 kg
Initial velocity (U) = 28.9 m/s
Time (t) = 1.85 ms = 1.85x10^-3s
Final velocity (V) = 37.0 m/s
Force (F) =?
Step 2:
Determination of the magnitude of the horizontal force applied. This can be obtained by applying the formula:
F = m(V + U) /t
F = 0.140(37+ 28.9) /1.85x10^-3
F = 9.226/1.85x10^-3
F = 4987N
Therefore, the magnitude of the horizontal force applied is 4987N
