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tresset_1 [31]
3 years ago
7

Is there a way to see moon and the sun at once?

Physics
2 answers:
Arisa [49]3 years ago
4 0
Yes there is a way to see the moon and sun at once when the sun is setting and the moon is rising
sashaice [31]3 years ago
3 0

Earth rotates once a day, but the moon orbits Earth once every 28 days, so its position in the sky at a given time of day moves east by 360/28=13 degrees (roughly) each day.

The sun would appear in (roughly) the same spot in the sky at the same time each day except for the Earth’s axial tilt which causes it to move north and south with the seasons.

Necessarily, then, the sun moves through our entire sky each day, while the moon moves through our entire sky each month, sometimes appearing on the opposite side of Earth from the sun, sometimes on the same side.

It’s a stunningly common misconception that the moon is only seen at night. Quite the contrary, the moon is visible most days of the month—it’s just more likely to be close to full and therefore more noticeable when it’s out at night.

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If we want to describe work, we must have
kramer

The correct answer is C because why would you want to move the force away from the force. So therefore the answer C because you want to move the force to the force. Hope This Helps

6 0
4 years ago
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A 5.0-kg box is pulled by a horizontal force F applied to the top of the box. When the box meets a low doorstep, it begins to ro
NARA [144]

Answer:

the required minimum magnitude of the force F is 21 N

Explanation:

Given the data in the question,

m = 5 kg

width  = 60 cm

height = 80 cm

Let force is F represent in the image below,

so when the block about to rotate normal shifted to edge of cube

mg(w/2) = Fh

F = mg(w/2) / h

we know that g = 9.8 m/s²

we substitute

F = (5 × 9.8 ( 60/2)) / 70

F = (5 × 9.8 × 30 ) / 70

F = 1470 / 70

F = 21 N

Therefore, the required minimum magnitude of the force F is 21 N

5 0
3 years ago
A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof a time of 1.19s lat
victus00 [196]

Answer / Explanation

It is worthy to note that the question is incomplete. There is a part of the question that gave us the vale of V₀.

So for proper understanding, the two parts of the question will be highlighted.

A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof a time of 1.19s later. You may ignore air resistance.

a) What must the height of the building be for both balls to reach the ground at the same time if (i) V₀ is 6.0 m/s and (ii) V₀ is 9.5 m/s?

b) If Vo is greater than some value Vmax, a value of h does not exist that allows both balls to hit the ground at the same time.  

Solve for Vmax

Step Process

a)  Where h = 1/2g [ (1/2g - V₀)² ] / [(g - V₀)²]

Where V₀ = 6m/s,

We have,

           h = 4.9 [ ( 4.9 - 6)²] / [( 9.8 - 6)²]

                 = 0.411 m

Where V₀ = 9.5m/s

We have,

     h = 4.9 [ ( 4.9 - 9.5)²] / [( 9.8 - 9.5)²]

                 = 1152 m

b)  From the expression above, we got to realise that h is a function of V₀, therefore, the denominator can not be zero.

Consequentially, as V₀ approaches 9.8m/s, h approaches infinity.

Therefore Vₙ = V₀max = 9.8 m/s

4 0
3 years ago
________ law is called the law of partial pressure
Studentka2010 [4]
Dalton's <span>law of partial pressures
</span>
6 0
3 years ago
When the Sun is directly overhead, the intensity of sunlight reaching the ground is about 1000 W/m^{2} 2 . The Earth has a radiu
Hunter-Best [27]

Answer:

The total power associated with sunlight shining on the Earth is 8.04 × 10^10W

Explanation: Please see the attachment below

6 0
3 years ago
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