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3 years ago

1. A baseball coach graphs some data and finds the line of

Mathematics

1 answer:

Vlada [557]3 years ago

6 0

The answer to this is 35 because i did caculation and thats the answer it gave me

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4000 principal earning 7% compounded annually , 7 years

katrin [286]

4000×7×7÷100 that is your answer u have to divide it

5 0

3 years ago

Need help ASAP!!!!!!!!!!!!

Yakvenalex [24]

I cant see 5th question....
Rest are attched below

4 0

4 years ago

Esteban has a big jar of change in his room. He has 600 coins total, and 240 of them are pennies. What percentage of the coins a

Thepotemich [5.8K]

<h2>40 % of coins are pennies.</h2>

Step-by-step explanation:

Total number of coins = 600

Total number of pennies = 240

$\texttt{Percentage of the coins are pennies=}\frac{\texttt{Total number of pennies}}{\texttt{Total number of coins}}\times 100\\\\\texttt{Percentage of the coins are pennies=}\frac{240}{600}\times 100\\\\\texttt{Percentage of the coins are pennies=}\frac{240}{6}\\\\\texttt{Percentage of the coins are pennies=}\frac{120}{3}\\\\\texttt{Percentage of the coins are pennies=}40\%$

40 % of coins are pennies.

3 0

4 years ago

Read 2 more answers

Find all the zeros of the equation x^4-6x^2-7x-6=0

rusak2 [61]

Answer:

The zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Step-by-step explanation:

We have been given the equation x^4-6x^2-7x-6=0

Use rational root theorem, we have

$a_0=6,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:3,\:6,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:3,\:6}{1}$

$-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2$

$=\left(x+2\right)\frac{x^4-6x^2-7x-6}{x+2}\\$

$=x^3-2x^2-2x-3$

Again factor using the rational root test, we get

$=\left(x+2\right)\left(x-3\right)\left(x^2+x+1\right)$

Using the zero product rule, we have

$x+2=0:\quad x=-2\\x-3=0:\quad x=3\\x^2+x+1=0\\\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\\\=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Therefore, the zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

4 0

3 years ago

Read 2 more answers

Xy + 3ey = 3e, find the value of y'' at the point where x = 0.

Katyanochek1 [597]

y might be 1 and I got that cuz 0y+3ey=3e and replace y with 1 and you get 0•1+3e•1=3e and to be honest it kinda looks like it makes sense

7 0

3 years ago

Read 2 more answers