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3 years ago

How would you describe the paths pictured below?

Mathematics

1 answer:

stepladder [879]3 years ago

6 0

It would be B, none of these

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The diagonal of rectangle ABCD measures 2 inches in

ryzh [129]

Answer:

B. √3

Step-by-step explanation:

Edge 2021

7 0

3 years ago

For what values of a does the equation a+x= 1+xa^2 have no solution?

Anton [14]

Answer:

We have the equation

$a+x= 1+xa^2$

we leave the terms with x on the left side of the equation and the independent terms on the right side.

$x-xa^2=1-a\\(1-a^2)x=1-a\\$

resolving for x we have that

$x=\frac{1-a}{1-a^2}$

Since we need that the equation doesn't have solution, then it is necessary that the denominator of x be 0 and this occur when $1-a^2=0\\1=a^2\\a=\pm1$

Then, for $a=\pm1$ the equation hasn't solution

7 0

3 years ago

Pleaseee help me out !!!

Dahasolnce [82]

Answer:

y = 16

Step-by-step explanation:

y = 11 - x

of x is -5, subtitute it into the equation

y = 11 - (-5)

y = 11 + 5

y = 16

8 0

2 years ago

Read 2 more answers

What is the BEST evidence that the author would make a good sportswriter?

Nikolay [14]

Answer:

Step-by-step explanation:

The poem itself, which is a funny description of sports.

5 0

2 years ago

Read 2 more answers

Find the hypotenuse of an isosceles right triangle when the legs each measure 3\sqrt{x} 2inches.

Tresset [83]

The hypotenuse of the right triangle measures 3 units.

<h3>How to find the hypotenuse?</h3>

Here we know that both legs measure:

$L =\frac{3}{\sqrt{2} }$

If we use the Pythagorean theorem, we will see that the hypotenuse H can be written as:

$H^2 = (\frac{3}{\sqrt{2} } )^2 + (\frac{3}{\sqrt{2} } )^2 \\\\H^2 = \frac{9}{2} + \frac{9}{2} = \frac{18}{2} = 9\\\\H = \sqrt{9} = 3$

Then we conclude that the hypotenuse of the right triangle measures 9 units.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

6 0

2 years ago