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Kazeer [188]
2 years ago
13

if i mix blue gatorade with red gatorade what do i get this is for my science exam right now please answer

Chemistry
1 answer:
Gnesinka [82]2 years ago
7 0

Answer:

purple gatorade

Explanation:

:)

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The melting point of gallium is 85.59°F (29.77°C).
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What determines how ionic bonds will form?
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I think the answer should be B. Number of valence electrons

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What does density have to do with the cycling of matter in earths interior
Anastaziya [24]

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The rocks of higher density inter the mantle. Due to density they sink and melt. When they melt the density decreases and rises to the top. They then are recycled through volcanoes.  

Explanation:

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3 years ago
A chemist must prepare of sodium hydroxide solution with a pH of at . He will do this in three steps: Fill a volumetric flask ab
77julia77 [94]

Answer:

0.0400 g for the example given below.

Explanation:

pH value is not provided, so we'll solve this problem in a general case and then we will use an example to justify it.

  • By definition, pH = -log[H_3O^+].
  • NaOH is a strong base, as it's a hydroxide formed with a group 1A metal, so it dissociates fully in water by the equation: NaOH (aq)\rightarrow Na^+ (aq) + OH^- (aq).
  • From the equation above, using stoichiometry we can tell that the molarity of hydroxide is equal to the molarity of NaOH: [NaOH] = [OH^-].
  • Concentration of hydroxide is then equal to the ratio of moles of NaOH and the volume of the given solution. Moles themselves are equal to mass over molar mass, so we obtain: [OH^-] = [NaOH] = \frac{n_{NaOH}}{V} = \frac{m_{NaOH}}{M_{NaOH}V}.
  • We also know that pOH = 14.00 - pH = -log[NaOH]. Take the antilog of both sides: 10^{-pOH} = 10^{pH - 14.00} = [NaOH] = \frac{m_{NaOH}}{M_{NaOH}V}.
  • Solve for the mass of NaOH: m_{NaOH} = 10^{pH - 14.00}\cdot M_{NaOH}\cdot V.

Now, let's say that pH is given as 12.00 and we use a 100-ml volumetric flask. Then we would obtain:

m_{NaOH} = 10^{12.00 - 14.00}\cdot 39.997 g/mol\cdot 0.100 L = 0.0400 g

7 0
3 years ago
Choose the correct net ionic equation for the reaction (if a reaction occurs) between CaCl2 and AgNO3: Group of answer choices
Levart [38]

Answer:

2Ag⁺(aq) + 2Cl⁻(aq) -> 2AgCl(s)

Explanation:

Silver nitrate and calcium chloride will react in a double displacement reaction (which has to produce a precipitate, a gas, or water to have a reaction).

This reaction will produce a silver chloride precipitate and a solution of calcium nitrate.

The reaction will be 2AgNO3(aq) + CaCl2(aq) -> 2AgCl(s) + Ca(NO3)2(aq)

To write a net ionic equation:

1. Write the balanced molecular equation.

   2AgNO3 + CaCl2 -> 2AgCl(ppt) + Ca(NO3)2

2. Write the balanced complete ionic equation.

To write the complete ionic equation:

- Start with a balanced molecular equation.

2AgNO3(aq) + CaCl2(aq) -> 2AgCl(s) + Ca(NO3)2(aq)

- Break all soluble strong electrolytes (compounds with (aq) beside them) into their ions

       indicate the correct formula and charge of each ion

       indicate the correct number of each ion

       write (aq) after each ion

- Bring down all compounds with (s), (l), or (g) unchanged.

2Ag⁺(aq) + 2NO³⁻(aq) + Ca²⁺(aq) + 2Cl⁻(aq) -> 2AgCl(s) + Ca²⁺(aq) + 2NO³⁻(aq)

3. Cross out the spectator ions that are present. Spectator ions are ions that are present in the reaction mixture but do not participate in it. You can recognize spectator ions by looking for ions that are present on both sides of the equation.

4. Write the "leftovers" as the net ionic equation.

2Ag⁺(aq) + 2Cl⁻(aq) -> 2AgCl(s)

4 0
3 years ago
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