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dexar [7]
3 years ago
15

PLEASE HELPPP!!The property of water that allows it to carry ions to the heart is its:

Chemistry
1 answer:
Alex17521 [72]3 years ago
7 0

Explanation:

The property of water that allows it to carry ions to the heart is its polarity.

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Which two kinds of energy are associated with flames?
nekit [7.7K]

Answer:

Type= Thermal Energy , Motion = Random motion of microscopic particles of matter , Example = Heat, Fire

Type= Electrical energy, Motion = Bluk flow of chorges , Example = Household current , AC and DC circuits.

Explanation:

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3 years ago
The sum of the protons and neutrons in the nucleus of an atom is called the _____?
True [87]
The sun of the protons a D neutrons in the nucleus of an atom is called the ATOMIC MASS
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3 years ago
The reaction A(B) = 2B(g) has an equilibrium constant of K = 0.045. What is the equilibrium constant for the reaction B(g) =1/2A
Mamont248 [21]

Answer:

The  K_c for the reaction B(g) = \frac{1}{2}A will be 4.69.

Explanation:

The given equation is A(B) = 2B(g)

to evaluate equilibrium constant for B(g) = \frac{1}{2}A

            K_c=[B]^2[A]

                 = 0.045

The reverse will be 2B\leftrightharpoons A

Then,      K_c = \frac{[A]}{[B]^2}

                    =  \frac{1}{0.045}

                    = 22m^{-1}

The equilibrium constant for B(g) = \frac{1}{2}A will be

               K_c = \sqrt{K_c}

                    =\sqrt{22}

                    = 4.69

Therefore, K_c for the reaction B(g) = \frac{1}{2}A will be 4.69.

5 0
3 years ago
For the following reaction, the equilibrium constant Kc is 0.80 at a certain temperature. If the concentration of NO(g) and NOBr
velikii [3]

Answer:

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        2NO (g)  +  Br₂ (g)   ⇄   2NOBr (g)

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That's the situation told, in the statement.

Let's make the expression for Kc

Kc = [NOBr]² / [Br₂] . [NO]²

Kc = 0.80² / [Br₂] . [0.80]²

0.80 = 1 / [Br₂]

[Br₂] = 1 / 0.80 → 1.25

4 0
3 years ago
How many sig figs are in 340.0 mL
lyudmila [28]

Answer:

4

Explanation:

there is a decimal place present. so you would take away any zeros before the number.

5 0
3 years ago
Read 2 more answers
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