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3 years ago

According to its periodic table entry, how many electrons does nitrogen have in its valence level?

1 answer:

3 0

The valence level of an atom refers to the number of electrons that reside in the upper most energy level. Nitrogen has an atomic number of 7 and therefore has 7 electrons. The first energy level (1) holds 2 electrons, leaving 5 electrons to reside in the second energy level (2s and 2p). Therefore the valence of nitrogen is 5.

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Una síntesis industrial del acetileno, gas extensamente utilizado para la fabricación de numerosas drogas, colorantes y plástico

astraxan [27]

Answer:

foot dab lit foot you a foot

3 0

2 years ago

Assume the molality of isoborneol in your product is 0.275 mol/kg. What is the melting point of your impure sample given that th

aliina [53]

Answer:

168°C is the melting point of your impure sample.

Explanation:

Melting point of pure camphor= T =179°C

Melting point of sample = $T_f$ = ?

Depression in freezing point = $\Delta T_f$

Depression in freezing point is also given by formula:

$\Delta T_f=i\times K_f\times m$

$K_f$ = The freezing point depression constant

m = molality of the sample = 0.275 mol/kg

i = van't Hoff factor

We have: $K_f$ = 40°C kg/mol

i = 1 ( non electrolyte)

$\Delta T_f=1\times 40^oC kg/mol\times 0.275 mol/kg$

$\Delta T_f=11^oC$

$\Delta T_f=T- T_f$

$T_f=T- \Delta T_f=179^oC-11^oC=168^oC$

168°C is the melting point of your impure sample.

4 0

3 years ago

The oxidation number of all the element in free state is 0

Art [367]

Answer:

Zero-Nine

Explanation:

this is becasue these numbers are rather small and if you plug these numbers into an equation you will most likely get 0.

8 0

2 years ago

. A container with a volume of 0.50 L contains air at a pressure of 1.0 atm. If the volume is reduced to 0.10 L at constant temp

marin [14]

Answer:

The answer to your question is Pressure = 5 atm

Explanation:

Data

Volume 1 = V1 = 0.5 l

Pressure 1 = P1 = 1 atm

Volume 2 = V2 = 0.1 l

Pressure 2 = P2 = x

Formula

To solve this problem use the Boyle's equation

V1P1 = V2P2

Solve for P2

P2 = V1P1/V2

Substitution

P2 = (0.5 x 1) / 0.1

Simplification

P2 = 0.5/0.1

Result

P2 = 5 atm

3 0

3 years ago

How many mL of a .132 M aqueous solution of sodium chloride, NaCl, must be taken to obtain 3.59 grams of the salt?

Sever21 [200]

Answer:

465mL

Explanation:

Volume of a solution, V =Mass of substance, m/(Molarity of the solution of the substance, M × molar mass of the substance, M.m)

Given in the question,

M=.132M

M.m=23+35.5 = 58.5g/mol

m=3.59g

V= 3.59/(.132×58.5)

V = 0.465L

Volume in mL = volume in L × 1000

= 0.465 × 1000 = 465mL

Therefore, 465mL of a .132M aqueous solution of sodium chloride, NaCl, must be taken to obtain 3.59 grams of the salt

4 0

3 years ago