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Sidana [21]
2 years ago
10

A layer of sandstone is found on top of a layer of shale

Chemistry
1 answer:
alex41 [277]2 years ago
5 0

Answer: Yes it is

Explanation:

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A student cleaned their glassware with tap water (known to contain chloride ions). They then attempted to make a 0.020 M solutio
Rina8888 [55]

Answer:

Ag⁺(aq) + Cl⁻(aq) → AgCl(s)

Explanation:

The silver nitrate, AgNO₃, dissolves in water as follows:

AgNO₃(aq) → Ag⁺(aq) + NO₃⁻(aq)

The Ag⁺ reacts with Cl⁻ producing AgCl(s), a white insoluble salt. The net ionic equation that describes the formation of the precipitate is:

<h3>Ag⁺(aq) + Cl⁻(aq) → AgCl(s)</h3><h3 /><h3 />
4 0
2 years ago
What is the molecular formula for chloroform? none of these choices CH3C CHCI3 CH2C12 CCI4
dangina [55]

Answer:

CHCI₃

Explanation:

Chloroform, IUPAC name, trichloromethane, is organic compound with the molecular  formula CHCl₃. It is colorless and sweet-smelling liquid having high density which is produced on a large scale precursor of PTFE , and for various refrigerants .

Chloroform , is a powerful euphoriant , anxiolytic , anesthetic and sedative when inhaled or ingested .

4 0
3 years ago
Why is carbon used to extract metals from their oxides? ​
pashok25 [27]

Answer:

If a metal is less reactive than carbon, it can be extracted from its oxide by heating with carbon. The carbon displaces the metal from the compound, and removes the oxygen from the oxide. This leaves the metal.

Explanation:

4 0
2 years ago
If a star is 33.11 trillion kilometers away how much light years would that be
abruzzese [7]
33.11 trillion kilometers is equivalent to 3.5 light years

hope this helps :)<span />
8 0
3 years ago
At 25.0°c, a solution has a concentration of 3.179 m and a density of 1.260 g/ml. the density of the solution at 50.0°c is 1.249
oksano4ka [1.4K]

Answer: -

3.151 M

Explanation: -

Let the volume of the solution be 1000 mL.

At 25.0 °C, Density = 1.260 g/ mL

Mass of the solution = Density x volume

= 1.260 g / mL x 1000 mL

= 1260 g

At 25.0 °C, the molarity = 3.179 M

Number of moles present per 1000 mL = 3.179 mol

Strength of the solution in g / mol

= 1260 g / 3.179 mol = 396.35 g / mol (at 25.0 °C)

Now at 50.0 °C

The density is 1.249 g/ mL

Mass of the solution = density x volume = 1.249 g / mL x 1000 mL

= 1249 g.

Number of moles present in 1249 g = Mass of the solution / Strength in g /mol

= \frac{1249 g}{396.35 g/mol}

= 3.151 moles.

So 3.151 moles is present in 1000 mL at 50.0 °C

Molarity at 50.0 °C = 3.151 M

7 0
2 years ago
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