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Sidana [21]
3 years ago
10

A layer of sandstone is found on top of a layer of shale

Chemistry
1 answer:
alex41 [277]3 years ago
5 0

Answer: Yes it is

Explanation:

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Consider the Bohr model of the simplest atom, hydrogen. What energy photon will be released if an electron falls from the n= 2 o
Nana76 [90]
<h2>Ultraviolet Light</h2>

Explanation:

  • The energy of a photon that will be released if an electron falls from the n= 2 orbit (excited state) to the n0 = 1 orbit (ground state) is of ultraviolet light.
  • In the ultraviolet part of the spectrum, a photon having an energy of 10.2 eV has a wavelength of 1.21 x 10-7 m.
  • Hence, when an electron wants to jump or it gets excited from the first level to the second level that is from n = 1 orbit to n = 2 orbits, it must absorb a photon of ultraviolet light.
  • But,When an electron falls from n = 2 orbit to n = 1 orbit  or from n = 2 orbit(excited state) to n = 0 orbit(groubd state), it emits a photon of ultraviolet light.
7 0
3 years ago
Do you believe the research subjects in the original study were appropriate for this experiment
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4 0
3 years ago
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Oxidation number is
zavuch27 [327]
The correct letter to your answer would be A
5 0
3 years ago
Is this right? giving brainlt if you actually checked​
Maksim231197 [3]

Answer:

yes it is

Explanation:

5 0
2 years ago
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1. An electric power plant uses energy from burning coal to generate steam at 450 °C. The plant is cooled by 20 °C water
kap26 [50]

Answer:

Explanation:

Efficiency of the electric power plant is e=1-\frac{T_{2}}{T_{1}}

Here Temperature of hot source T_{1} = 450^{o}C=450+273=723 K

and Temperature of sink T_{1} = 20^{o}C=20+273=293 K

Hence the efficiency is  e=1-\frac{293}{723}=0.5947=59.47%

Now another formula for thermal efficiency Is

e_{therm}=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{W}{Q_{1}}

Here QI is the of heat taken from source 100 MJ ; Q2 of heat transferred to the sink (river) to be found

W is the of work done and W = QI -Q2

Hence Frome_{therm}=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{W}{Q_{1}}

W=e(Q_{1})=(0.5947)(100)=59.47MJ

Hence the of heat transferred to the river Is Q_{2} -W = (100 -59.47=40.53

6 0
3 years ago
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