The bearing of point X <u>from</u> point Z is 285°
<h3>Calculating bearings </h3>
From the question, we are to determine the bearing of point X from point Z.
Consider the diagram attached
The bearing of point X <u>from</u> point Z is the measure of the angle from the North of Z in the <u>clockwise direction</u> to the line that goes to X.
That is,
The bearing of point X from point Z = 270° + 15°
The bearing of point X from point Z = 285°
Hence, the bearing of point X from point Z is 285°
Learn more on Calculating bearings here: brainly.com/question/22719608
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Anytime x = 0 in a point the y intercept is immediately defined.
y = mx + b The y intercept is b
y = 0 + b
0 = 0 + b
b = 0
What you know so for is
y = mx + b
y = mx since b = 0
7 = m*1
m = 7
The answer is y = 7x <<<<<<Answer.
Answer:
y=3x+2
Step-by-step explanation:
Answer:19683x
Step-by-step explanation:
Evaluate the exponent
27.93x
27.729x
i am pretty sure sorry if I am wrong
Replace ‘x’ with what ever number and then add 2, because if you make x a 1 then you would get a three. the equation goes from (x+2)=y to (1+2)=3 so make x whatever you want and then add 2 and you’ll get your ‘y’