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Kruka [31]
2 years ago
5

F

Mathematics
1 answer:
elixir [45]2 years ago
8 0

Answer:

x=closest to 12m

Step-by-step explanation:

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a typical marathon is 26.2 miles Aleexis averages 12 km per 1 hour when running in marathons. Use dimensional Analysis to determ
yanalaym [24]
3 hours and 51 minutes
5 0
3 years ago
54394 plus 13768<br><br><br> Thank you
kakasveta [241]

Answer:

54394 + 13768 \\  \\  = 68162

5 0
3 years ago
Read 2 more answers
The school that Lisa goes to is selling tickets to the annual talent show. On the first day of ticket sales the school sold 4 se
kakasveta [241]
Let:
x = cost of senior citizen ticket
y = cost of student ticket

4x + 5y = 102
7x + 5y = 126

4x + 5y = 102
4x = 102 - 5y
x = (102 - 5y)/4
x = 102/4 - 5y/4

7x + 5y = 126
7(102/4 - 5y/4) + 5y = 126
(714/4 - 35y/4) + 5y = 126
-35y/4 + 5y = 126 - 714/4

note:
-35y/4 = -8.75y
714/4 = 178.5

-8.75y + 5y = 126 - 178.5
-3.75y = -52.5
y = -52.5/-3.75
y = 14


x = 102/4 - 5y/4
x = 102/4 - 5(14)/4
x = 8

x = cost of senior citizen ticket = $8/ea
y = cost of student ticket = $14/ea



6 0
3 years ago
A TV has a listed price of $ 682.98 before tax. If the sales tax rate is 6.25% , find the total cost of the TV with sales tax in
Drupady [299]

Answer:

725.7

Step-by-step explanation:

you multiply 682.98 x 6.25% and get 42.68625

then you add 682.98 + 42.68625 and get 725.66625

then you have to round to the nearest hundredth and get 725.7.

6 0
3 years ago
Sally lives in City A and works for the department of transportation. She needs to inspect the weigh stations in each of four di
galben [10]

Answer:

She can visit the cities in 192 ways

Step-by-step explanation:

If Sally starts from city A and after going to 4 cities she returns to home,

then that can be in 4! = 24 ways. (permutation of 4 distinct objects)

If between the time she visits cities, she comes home once,

then cities can be visited in,

4! \times 3_{C_{1}} = 72 ways.  (permutation of 4      distinct objects  and choosing 1 gap among the 3 )

If between the time she visits cities, she comes home twice,

then cities can be visited in,

4! \times 3_{C_{2}} =72 ways. (permutation of 4 distinct objects and finding 2 gaps among the 3)

If between the time she visits cities, she comes home thrice,

then cities can be visited in,

4! \times 3_{C_{3}} = 24 ways. (permutation of 4 distinct objects and choosing 3 gaps among the 3)

Now, she can't come home more than thrice in between the time she visits cities (since there are 4 cities to visit only)

So, the number of ways she can visit cities = (24+ 72 + 72 + 24)

                                                                       = 192

6 0
3 years ago
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