All categories

3 years ago

If you start with 1.000 gram sample of the isotope how much time would pass before you have just 0.100 grams of the isotope left

Chemistry

1 answer:

Vadim26 [7]3 years ago

6 0

Answer:

So, you're dealing with a sample of cobalt-60. You know that cobalt-60 has a nuclear half-life of

5.30

years, and are interested in finding how many grams of the sample would remain after

1.00

year and

10.0

years, respectively.

A radioactive isotope's half-life tells you how much time is needed for an initial sample to be halved.

If you start with an initial sample

, then you can say that you will be left with

→

after one half-life passes;

⋅

→

after two half-lives pass;

⋅

→

after three half-lives pass;

⋅

→

after four half-lives pass;

⋮

Explanation:

now i know the answer

You might be interested in

The process that occurs when physical forces break rock into smaller pieces without changing the rock's chemical composition is

sp2606 [1]

Answer:

A) Mechanical Weathering

Pls Mark As Brainliest!!!!!!!!!!!!!

Explanation:

Mechanical weathering breaks rocks into smaller pieces without changing their composition. Ice wedging and abrasion are two important processes of mechanical weathering. Chemical weathering breaks down rocks by forming new minerals that are stable at the Earth's surface

4 0

3 years ago

Single-replacement reactions

Ber [7]

The answer is C.

example: 3NaCl + Al ----> AlCl₃ + 3Na

5 0

3 years ago

Summarize the weather conditions related to a cold front. Remember to include all data collected on cold fronts in this activity

svp [43]

Answer: Many fronts cause weather events such as rain, thunderstorms, gusty winds and A weather front is a transition zone between two different air masses at the Lifted warm air ahead of the front produces cumulus or cumulonimbus clouds

Explanation:

Hope this was helpful

5 0

3 years ago

A mixture initially contains AA, BB, and CC in the following concentrations: [A][A]A_1 = 0.550 MM , [B][B]B_1 = 1.40 MM , and [C

Alex787 [66]

Answer:

The value of the equilibrium constant KC is 1.244

Explanation:

A mixture initially contains A, B, and C in the following concentrations: [A] = 0.550 M, [B] = 1.40 M, and [C] = 0.600 M. The following reaction occurs and equilibrium is established: A+2B<->C

At equilibrium, [A] = 0.430 M and [C] = 0.720 M. Calculate the value of the equilibrium constant, Kc

Step 1: The balanced equation

A+2B<->C

Step 2: The initial concentrations

[A] = 0.550 M

[B]= 1.40 M

[C] = 0.600 M

Step 3: The concentraions at equilibrium

[A] = 0.550 -X = 0.430 M

[B]= 1.40 -2X M

[C] = 0.600 + X = 0.720 M

X = 0.120 M

[A] = 0.550 - 0.120 = 0.430 M

[B]= 1.40 -2*0.120 = 1.16 M

[C] = 0.600 + 0.120 = 0.720 M

Step 4: Calculate Kc

Kc = [C] / [A][B]²

Kc = 0.720 / (0.430*1.16²)

Kc = 1.244

The value of the equilibrium constant KC is 1.244

5 0

4 years ago

A researcher wants to test the solubility (property of being dissolved) of salt in water as the temperature of the water increas

aev [14]

Have about 5 beakers all with different temperatures of water. Put in a teaspoon of salt at a time and when it stops dissolving stop adding and record how much salt it took. It should be more salt as the temperature rises. The independent variable is the waters temperature. The dependent variable is how much salt is used. Make sure that there is the same amount of water in each beaker. Or else it won’t work.

6 0

3 years ago