Answer:
Tests for gases
Hydrogen, oxygen, carbon dioxide, ammonia and chlorine can be identified using different tests.
Hydrogen. A lighted wooden splint makes a popping sound in a test tube of hydrogen.
Oxygen. A glowing wooden splint relights in a test tube of oxygen.
hope it will help
Exothermic reactions release heat the surrounding. So Freezing?
Answer:
Consciousness refers to your individual awareness of your unique thoughts, memories, feelings, sensations, and environments. Essentially, your consciousness is your awareness of yourself and the world around you. This awareness is subjective and unique to you.
Explanation:
Missing question: what is the density of 53.4 wt% aqueous NaOH if 16.7 mL of the solution diluted to 2.00L gives 0.169 M NaOH?
Answer is: density is 1.52 g/mL.
c₁(NaOH) = ?; molarity of concentrated sodium hydroxide.
V₁(NaOH) = 16.7 mL; volume of concentrated sodium hydroxide.
c₂(NaOH) = 0.169 M; molarity of diluted sodium hydroxide.
V₂(NaOH) = 2.00 L · 1000 mL/L = 2000 mL; volume of diluted sodium hydroxide.
Use equation: c₁V₁ = c₂V₂.
c₁ = c₂V₂ / V₁.
c₁ = 0.169 M · 2000 mL / 16.7 mL.
c₁(NaOH) = 20.23 M.
m(NaOH) = 20.23 mol · 40 g/ml.
m(NaOH) = 809.53 g.
The mass fraction is the ratio of one substance (in this example sodium hydroxide) with mass to the mass of the total mixture (solution).
Make proportion: m(NaOH) : m(solution) = 53.4 g : 100 g.
m(solution) = 1516 g in one liter of solution.
d(solution) = 1516 g/L = 1.52 g/mL.
Answer:
The correct answer is 0.25 moles NH₃
Explanation:
First, we need to know the chemical equation for NH₃ formation from H₂. The balanced chemical reaction involved in NH₃ obtention is the following:
N₂(g) + 3 H₂(g) → 2 NH₃(g)
According to this, 2 moles of NH₃ are formed from 3 moles of H₂. We can write that estequiometrical relation as: 2 moles NH₃/ 3 moles H₂.
From the problem, we have to calculate how many moles of NH₃ are produced from 0.37 moles H₂. So, we can simply multiply the number of moles of H₂ to obtain by the convertion factor:
0.37 moles H₂ x 2 moles NH₃/ 3 moles H₂= 0.246 moles NH₃ ≅ 0.25 moles NH₃
Thus, 0.25 moles of NH₃ will be obtained.
