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Olin [163]
3 years ago
9

1-calculate the mass of 4 moles of Na

Chemistry
1 answer:
noname [10]3 years ago
6 0

1. 92 g

2. 5.4 g

3. 0.217 moles

<h3>Further explanation  </h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass

\tt n=\dfrac{m}{MW}

1. the mass of 4 moles of Na(MW= 23 g/mol)

\tt mass=mol\times MW\\\\mass=4\times 23\\\\mass=92~g

2.  the mass of 0.3 moles of water(MW=18 g/mol)

\tt mass=mol\times MW\\\\mass=0.3\times 18\\\\mass=5.4~g

3. the number of moles found in 10g of ethanol C2H5OH(MW=46 g/mol) :

\tt mol=\dfrac{10}{46}\\\\mol=0.217

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4 years ago
Which of these solutions are basic at 25 °C? Solution A: [OH−]=3.13×10−7 M Solution C: [H3O+]=0.000747 M Solution B: [H3O+
solong [7]

Answer:

Are basic:

[OH⁻] = 3.13x10⁻⁷M and [H₃O⁺] = 9.55x10⁻⁹M

Explanation:

A solution is basic when pH = - log [H₃O⁺] is higher than 7.

It is possible to convert [OH⁻] to [H₃O⁺] using:

[H₃O⁺] = 1x10⁻¹⁴ / [OH⁻]

a. [OH⁻] = 3.13x10⁻⁷M

[H₃O⁺] = 1x10⁻¹⁴ / [3.13x10⁻⁷M]

[H₃O⁺] = 3.19x10⁻⁸M

pH = - log [H₃O⁺] = 7.50

[OH⁻] = 3.13x10⁻⁷M is basic

b. pH = -log [H₃O⁺] = - log 0.000747M = 3.13.

This solution is not basic

c. [H₃O⁺] = 9.55x10⁻⁹M

pH = 8.02

This solution is also basic.

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How many grams of sodium carbonate, Na2CO3, are needed to add to 0.125 kg of water to make a 0.200 m (molal) solution
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Answer:

Mass = 2.65 g

Explanation:

Given data:

Mass of sodium carbonate = ?

Mass of water = 0.125 g

Molality = 0.200 m

Solution:

Formula:

Molality = number of moles of solute / mass of solvent in Kg

by putting values,

0.200 m = Number of moles of solute / 0.125 kg

Number of moles = 0.200 m × 0.125 kg

Number of moles = 0.025 mol

Mass of sodium carbonate:

Mass = number of moles × molar mass

Mass = 0.025 mol × 106 g/mol

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