Answer:
CHN
Explanation:
Please see attached picture for working.
Answer: 6.75 moles of
can be produced from 13.5 moles Na
Explanation:
The balanced chemical equation for formation of
from Na is:
According to stoichiometry :
4 moles of Na give = 2 moles of
Thus 13.5 moles of
give =
of
Thus 6.75 moles of
can be produced from 13.5 moles Na
Answer:
1.4952 grams of sodium bicarbonate she would need to ingest to neutralize this much HCl.
Explanation:

Moles of hydrochloric acid = n
Volume of hydrochloric acid solution = 200.0 mL = 0.200 L
Molarity of the hydrochloric acid = 0.089 M
of HCL

According to reaction, 1 mole of HCl is neutralized by 1 mole of sodium bicarbonate.
Then 0.0178 moles of HCl wil be neutralized by :
of sodium bicarbonate
Mass of 0.0178 moles of sodium bicarbonate:
0.0178 mol × 72 g/mol = 1.4952 g
1.4952 grams of sodium bicarbonate she would need to ingest to neutralize this much HCl.